Priyam Alok
IiTeachChem
•Created by hardcoreisdead on 1/27/2025 in #💭│doubts
how to do
"friction chahata hai ki 2 body contact me rahe,uske liye friction tabhi lagega jab jarurat ho, utna hi lagega jitne ki jarurat ho aur wahin lagegaa jahan jarurat ho"
Thoda cringe ya weird lines ho sakti but kaam ki baaten hai
18 replies
IiTeachChem
•Created by hardcoreisdead on 1/27/2025 in #💭│doubts
how to do
Don't follow any short trick just stick to basic
18 replies
IiTeachChem
•Created by simplybear on 1/26/2025 in #💭│doubts
how do u do these kind of ques
The thing is that there is no instantaneous change in spring when string is cut but in steady state the spring force will be changed
30 replies
IiTeachChem
•Created by camus on 1/14/2025 in #💭│doubts
Moment of Inertia question doubt
But i think ring must be right choice here
28 replies
IiTeachChem
•Created by camus on 1/14/2025 in #💭│doubts
Moment of Inertia question doubt
The thing is that the answer may differ if we take disc
28 replies
IiTeachChem
•Created by camus on 1/14/2025 in #💭│doubts
Moment of Inertia question doubt
Galti se muh se nikal gya tha XD
28 replies
IiTeachChem
•Created by camus on 1/14/2025 in #💭│doubts
Moment of Inertia question doubt
I mean parallel axis th
28 replies
IiTeachChem
•Created by camus on 1/14/2025 in #💭│doubts
Moment of Inertia question doubt
@camus
28 replies
IiTeachChem
•Created by camus on 1/14/2025 in #💭│doubts
Moment of Inertia question doubt
Parallel axis th se hoga
28 replies
IiTeachChem
•Created by camus on 1/14/2025 in #💭│doubts
Moment of Inertia question doubt
Is the answer 2
28 replies
IiTeachChem
•Created by hardcoreisdead on 10/6/2024 in #💭│doubts
parabola 2
\begin{aligned}&Tangent : y^{2}=4ax\&\Rightarrow y=mx+\frac{a}{m}\&Normal:x^{2}=4by\&y=mx+2b+\frac{b}{m^{2}}\&Comparing\rightarrow2b+\frac{b}{m^{2}}=\frac{a}{m}\&\Rightarrow2bm^{2}-am+b=0\&D>0\Rightarrow a^{2}-8b^2>0\end{aligned}
38 replies
IiTeachChem
•Created by Lindane on 10/21/2024 in #💭│doubts
Application of cross product
@Lindane
6 replies
IiTeachChem
•Created by Lindane on 10/21/2024 in #💭│doubts
Application of cross product
You might have done. Some calc mistake or taken wrong angle answer giver is indeed correct that is costheta = root 3/10
6 replies
IiTeachChem
•Created by SirLancelotDuLac on 10/18/2024 in #💭│doubts
Ray Optics
@SirLancelotDuLac
10 replies
IiTeachChem
•Created by SirLancelotDuLac on 10/18/2024 in #💭│doubts
Ray Optics
Di = f(θ)
So 2 x 10^-2 = f x 10^-2
So f = 2
By lens maker formula R = 2m
10 replies
IiTeachChem
•Created by SirLancelotDuLac on 10/18/2024 in #💭│doubts
Ray Optics
Assuming refractive index of lens = 1.5
10 replies