parabola 2
For what values of 'a' will the tangents drawn to the parabola y^2=4ax
from a point, not on the y-axis, will be normal to the parabola x^2=4by
30 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.i tried taking tangent of y^2=4ax in parametric form and compared with the parametric normal of x^2=4by but didnt really get smthing , did same with slope forms
Is it (-2root2,2root2) ?
jsut the opposite of it
R-(-2root2,2root2)
ahh same thing
huh?
Tumne jo likha mene bhi to whi likha
u wrote a ki range right
but uski ulti hai
ans dikha skta ho kya given hai iska?
a<-2root2 a>2root2
wait thats another one of similar type usmein b=1 dia hai
actual answer is a^2>8b^2
Ehh i might hve made some calculation mistake ill share the soln once im done with my classes
ping me in case i forget
@Real potato ?
Oh i just saw its x^2=4by i solved by taking x^2=4y
are you sure this is the que?
yep
oh if thats the case wht i did wont work here let me try smthg else then
@Real potato kuch bana?
banana toh aapko hai xD
sort hua?
naah
uhh sorry dude i was too much busy with my classes n tests
kya scene bro :D
@hardcoreisdead please send a picture of the question instead of typing it
@iTeachChem please consider making a rule for this if possible. Students bring handwritten questions to me a lot of times and they turn out to be wrong, like a mistake in copying which just turns out to be a waste of time. So I’ve stopped trying questions like this at all lol
It’s always better to see the question printed somewhere. Chances of an error are very less this way
Ah yes this is a good idea thanks!
@Moderator please note!
Thanks ♥️
Question with the given soln , I don't understand the soln tho
\begin{aligned}&Tangent : y^{2}=4ax\&\Rightarrow y=mx+\frac{a}{m}\&Normal:x^{2}=4by\&y=mx+2b+\frac{b}{m^{2}}\&Comparing\rightarrow2b+\frac{b}{m^{2}}=\frac{a}{m}\&\Rightarrow2bm^{2}-am+b=0\&D>0\Rightarrow a^{2}-8b^2>0\end{aligned}
Priyam Alok
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got it sir. thank you
+solved @πrate
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