24 Replies
@Gyro Gearloose
Note for OP
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Something to keep in mind is that the spring force never changes
Yep
ok so wait
if instead
spring was cut
Kx would be 0 but tension would still exist right
"just after it was cut"
Yep but the value of tension may change
huh
Something like this 👆
If spring is attached to support, its value remains constant throughout
If string attached to support, its value will change and its value = weight its holding
aj exam ke baad yeh samjhunga thank u 🙏
could anyone write the final spring force and the tension on both blocks just after cutting the spring?
@Prachi @stormycloud
If the spring is cut, then there will be no spring force and tension will be different
Spring force = 0
T on 2m = 0
T on m = 0
[pls correct if wrong it has been a few months since I studied this]
After the spring is cut, the string and the two masses will be in free fall , so their acceleration will be g and there will be no tension force on both the masses
My bad, I took it the wrong way
Changed
but T' on both is still acting, there is tension force individually on both
[Again pls correct if I am wrong]
This is how I see it,
2m block there is no upward force so there won’t be any opposite force, in this case T on 2m will be 0
m block there isn’t tension acting on it bc the 2m block is also moving with m block [u can compare this to the case where tension will act when the ceiling is fixed] so here even the “ceiling” is moving so there isn’t any necessity of tension
So here even if u remove the string both blocks fall with same acc as with string
does lcd pad feel better than pen paper?
It feels a littler smoother but the visibility is very poor imo
The thing is that there is no instantaneous change in spring when string is cut but in steady state the spring force will be changed
Ah makes sense thankyou so much