Nimboi
IiTeachChem
•Created by flower on 1/20/2025 in #💭│doubts
SHM
no point doing a question if your brain is fried
70 replies
IiTeachChem
•Created by flower on 1/20/2025 in #💭│doubts
SHM
and time period = 2pi/omega so compare and find
70 replies
IiTeachChem
•Created by flower on 1/20/2025 in #💭│doubts
SHM
which means you get the force as x(mg/L + K), which means the acceleration is x(g/L + K/m), which is equal to omega^2 x
70 replies
IiTeachChem
•Created by flower on 1/20/2025 in #💭│doubts
SHM
now since x is a very small displacement compared to L (because SHM), you can write the sqrt(L^2 - x^2) term as just L since L>>x
70 replies
IiTeachChem
•Created by flower on 1/20/2025 in #💭│doubts
SHM
you can get sin theta and cos theta by drawing the triangle of x and L when its displaced by theta, substitute values of sin and cos
70 replies
IiTeachChem
•Created by flower on 1/20/2025 in #💭│doubts
SHM
refer to video to understand
along the direction of the restoring force he mentioned, the force you'll get is mgsin(theta) + Kxcos(theta)
70 replies
IiTeachChem
•Created by flower on 1/20/2025 in #💭│doubts
SHM
look at it in the morning after trying
70 replies
IiTeachChem
•Created by flower on 1/20/2025 in #💭│doubts
SHM
ok ill leave some spoilered hints
70 replies
IiTeachChem
•Created by flower on 1/20/2025 in #💭│doubts
SHM
because in this case the restoring force is not only gravity, but also the spring force
70 replies
IiTeachChem
•Created by flower on 1/20/2025 in #💭│doubts
SHM
you'll need to go back to how the time period formula was derived
70 replies