dipole
yeah im still not able to solve que like this
three point charges +q,-2q and +q are placed at points (x=0,y=a,z=0), (x=0,y=0,z=0) and (x=a,y=0,z=0 respectively. the magnitude and direction of e;ectric dipole moment vector of this charge assembly are
8 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.-2q essentially just acts as 2 -q, which forms a dipole each with the +q charges
split -2q into 2 -q and now you have 2 dipoles with the two available +q chargesDipole is basically $q.\vec{r}$ right? Now split the -2q into 2 -q charges at the same place. Therefore one of the dipoles is $q.(a\hat{i})$ while the other is $q.a\hat{j}$
SirLancelotDuLac
SirLancelotDuLac
$$\vec{p} = (+q)(0\hat{i}+a\hat{j}+0\hat{k})+(-2q)(0\hat{i}+0\hat{j}+0\hat{k})+(+q)(a\hat{i}+0\hat{j}+0\hat{k})$$
$$\vec{p} = q(a\hat{i}+a\hat{j})$$
$$\vec{p} = aq(\hat{i}+\hat{j})$$
Opt
