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•Created by Werdox on 6/19/2024 in #help-and-questions

omit with condition

--- Here is the omitArray function for anyone finding this later

export function omitArray<Data extends object, Keys extends keyof Data>(
   data: Data[],
   keys: Keys[]
): Omit<Data, (typeof keys)[number]>[] {
   const result = [];

   for (const obj of [...data]) {
      const modifiedObj = { ...obj };
      for (const key of keys) {
         delete modifiedObj[key];
      }

      result.push(modifiedObj);
   }

   return result;
}

export function omitArray<Data extends object, Keys extends keyof Data>(
   data: Data[],
   keys: Keys[]
): Omit<Data, (typeof keys)[number]>[] {
   const result = [];

   for (const obj of [...data]) {
      const modifiedObj = { ...obj };
      for (const key of keys) {
         delete modifiedObj[key];
      }

      result.push(modifiedObj);
   }

   return result;
}

11 replies

PPrisma

•Created by Werdox on 6/19/2024 in #help-and-questions

omit with condition

Hmm I need the data in the original order. I do have an omitArray function which removes a property from all indecies of an array I guess I should use that then. Thought there might be a native solution.

11 replies

PPrisma

•Created by Werdox on 6/19/2024 in #help-and-questions

omit with condition

Pretty small for now, so no paginating

11 replies

PPrisma

•Created by Werdox on 6/19/2024 in #help-and-questions

omit with condition

Hmm this would be possible but it intentionally orders the list to type 1 and then type 0

11 replies

NNuxt