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iTeachChem
A Study Community for Everyone and Everything.We have weekly sessions on Spirituality, Math and Science! JEE, NEET prep? All doubts are crowdsourced. Hare Krishna!
JoinMotional EMF / Flux
in this question they just placed a emf source (metaphor for the Motional emf of rod) of value BVL but the flux is also changing for the closed loop shouldnt that also contribute to the current

Organic, mild hydrogenation confusion
The solution says A is
cis but-2-ene
But since there's no Lindlar's catalyst, A should be butane
right since there's nothing to stop unrestricted hydrogenation...
induced current due to rotating non-conducting sphere
the ans they have given is 8 what have I done wrong

hard adv or above lvl qs of 11th OC
im basically done with my coaching material and most of msc so can yall send more qs?
Algebra
in this question at last we get -8 and +16
p^2 + q^2 + 2pq = 4
P^2 + q^2 = 4 - 2pq by this logic pq cant be +16 but in ans it is why?...

Solutions, colligative property conceptual doubt
The number of moles of acetic acid here are = 45
number of moles of H2O here are = 150
We use the
Kf
of water here to get the correct answer because water has more moles
But acetic acid is definitely not negligible here...
Chem: Structure of pramanu(atom)
help please tumhara din accha ho jaye reason bhi dedena( with reason plz solve this question)

Kinematics
Radius of curvature is confusing. I thought of normal accln playing role, but don't know how exactly to write. I'll claim my kinematics too weak.
R= u^2/normal accln ...whts u and a exactly 🙂...

heat transfer
i have a few problems with the question.
1. "thermal conductivity is high " means majority of the heat is conducted and very low amount is absorbed and therfore emitted so how can we find out change of temp of A .
2. temp between the surfaces of A and B is to be taken 0K ??
3. masses are not given so how can we find out rate of change of temp...

Help?
Hi i need study session buddy for edexcel As level IAL business studies unit 2 please urgent help me ?❣️