induced current due to rotating non-conducting sphere
the ans they have given is 8 what have I done wrong
21 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.I got eight
It's a tad messy sorry
Oh I see your mistake. Really small one, but important. For each dθ, you have two charge elements, on either side of the axis.
So dq = Qdθ/π
Not 2π
fourth to fifth step how is extra /2 factor coming
Integration of sin²θ
I compensated for that by considering 2dq
I presume that's what you're asking
no before that
For μ/2?
yeah
.
That's from the formula.
$\frac{\mu_{0}ir^{2}}{2(r^{2}+z^{2})^{\frac{3}{2}}}$
Opt
that's fine see this once
Wait huh
I might have messed up
just that /2 rest is fine
so you are also getting 16
the method is correct right ?
Nope I'm wrong
I'm not thinking right
I think I just messed up there
16 seems right.
ok then
+solved @Opt
Post locked and archived successfully!
Archived by
<@726641475080683522> (726641475080683522)
Time
<t:1741884141:R>
Solved by
<@763645886500175892> (763645886500175892)