aabad_ankit Comments - Answer Overflow

Are you saying that using map it is possible to remove all the default from all the properties(nested or otherwise) (I dont' know the properties name which can have default)

25 replies

Aarktype

•Created by aabad_ankit on 10/3/2024 in #questions

Partial Application of the validator

Just a test example so I do need to validate a complete object without applying default values so .withoutOptionalAndDefaultMeta should solve my problem.

25 replies

Aarktype

•Created by aabad_ankit on 10/3/2024 in #questions

Partial Application of the validator

Any way to circumvent default values

const test = type({
  name: b,
  info: { email: "string.email & string.lower", age: "number=10" }
});
console.log(test.get("info")({email: "[email protected]"}));

const test = type({
  name: b,
  info: { email: "string.email & string.lower", age: "number=10" }
});
console.log(test.get("info")({email: "[email protected]"}));

Gives me { email: '[email protected]', age: 10 } dont want it to add age to it

25 replies

Aarktype

•Created by aabad_ankit on 10/3/2024 in #questions

Partial Application of the validator

Thank you so much for the quick response

25 replies

Aarktype

•Created by aabad_ankit on 10/3/2024 in #questions

Partial Application of the validator

Awesome. For my current use case get should be sufficient.

25 replies

Aarktype

•Created by aabad_ankit on 9/4/2024 in #questions

Can I add a default value to a type if everything other satisfies in a union type

Thank you so much for all the help

66 replies

Aarktype

•Created by aabad_ankit on 9/4/2024 in #questions

Can I add a default value to a type if everything other satisfies in a union type

@ArkDavid You were suggesting to use narrow, can I do it on union and solve my problem

66 replies

Aarktype

•Created by aabad_ankit on 9/4/2024 in #questions

Can I add a default value to a type if everything other satisfies in a union type

a code sample will be super useful

66 replies

Aarktype

•Created by aabad_ankit on 9/4/2024 in #questions

Can I add a default value to a type if everything other satisfies in a union type

but delete on undeclared key will work on union right once you have built in discrimination based on key presence

66 replies

Aarktype

•Created by aabad_ankit on 9/4/2024 in #questions

Can I add a default value to a type if everything other satisfies in a union type

const nameArk = type({ name: "string", age: "number" }).onDeepUndeclaredKey(
  "delete"
);
const cityArk = type({ city: "string" }).onDeepUndeclaredKey("delete");
const input = { name: "ark" };
const result = nameArk.or(cityArk)(input)
console.log(result.summary)

const nameArk = type({ name: "string", age: "number" }).onDeepUndeclaredKey(
  "delete"
);
const cityArk = type({ city: "string" }).onDeepUndeclaredKey("delete");
const input = { name: "ark" };
const result = nameArk.or(cityArk)(input)
console.log(result.summary)

This prints age must be a number (was missing) or city must be a string (was missing). I just want the error msg to be age must be a number (was missing) to do that I am currently doing something like this

const vm = {
  "name": nameArk,
  "city": cityArk
};
const input = { name: "ark" };
let result: typeof nameArk.infer | typeof cityArk.infer;
for (const key of keys(vm)) {
  if (key in input) {
    result = vm[key].assert(input);
    break;
  }
}

const vm = {
  "name": nameArk,
  "city": cityArk
};
const input = { name: "ark" };
let result: typeof nameArk.infer | typeof cityArk.infer;
for (const key of keys(vm)) {
  if (key in input) {
    result = vm[key].assert(input);
    break;
  }
}

so I wanted to know if there is more idiomatic way to do this

66 replies

Aarktype

•Created by aabad_ankit on 9/4/2024 in #questions

Can I add a default value to a type if everything other satisfies in a union type

@ArkDavid @Dimava the Monoreaper What will be the most idiomatic way to do the validation for such union types to get correct error msg. Do I need to check for the properties and do validation by creating a validator map

import { type } from "arktype";
import { keys } from "remeda";

const nameArk = type({ name: "string" }).onDeepUndeclaredKey("delete");
const cityArk = type({ city: "string" }).onDeepUndeclaredKey("delete");
const vm = {
  "name": nameArk,
  "city": cityArk
};
const input = { name: "ark" };
let result: typeof nameArk.infer | typeof cityArk.infer;
for (const key of keys(vm)) {
  if (key in input) {
    result = vm[key].assert(input);
    break;
  }
}

// peform pipe operation here

import { type } from "arktype";
import { keys } from "remeda";

const nameArk = type({ name: "string" }).onDeepUndeclaredKey("delete");
const cityArk = type({ city: "string" }).onDeepUndeclaredKey("delete");
const vm = {
  "name": nameArk,
  "city": cityArk
};
const input = { name: "ark" };
let result: typeof nameArk.infer | typeof cityArk.infer;
for (const key of keys(vm)) {
  if (key in input) {
    result = vm[key].assert(input);
    break;
  }
}

// peform pipe operation here

This is getting verbose. I am giving example of just one field but my inputs are larger and I have 5 different types of input. If I could have done union then I would have declared on deepUndeclaredkey("delete") on just the union as well as the pipe on the union

66 replies

Aarktype

•Created by aabad_ankit on 9/4/2024 in #questions

Can I add a default value to a type if everything other satisfies in a union type

Oh Yeah, Understood 👍

66 replies

Aarktype

•Created by aabad_ankit on 9/4/2024 in #questions

Can I add a default value to a type if everything other satisfies in a union type

I am getting name must be a string (was missing) or city must be a string (was missing) for both the code snippets below.

const type1 = type({"name": "string",age:"number","+": "delete"})
const type2 = type({"city": "string","+": "delete"})
const union = type([type1,"|",type2])
const result = union({"age":12})
console.log(result.summary)

const type1 = type({"name": "string",age:"number","+": "delete"})
const type2 = type({"city": "string","+": "delete"})
const union = type([type1,"|",type2])
const result = union({"age":12})
console.log(result.summary)

and

const type1 = type({ name: "string", age: "number", "+": "delete" }).pipe(
  (o) => {
    return { ...o, kind: "person" as const };
  }
);
const type2 = type({ city: "string", "+": "delete" }).pipe((o) => {
  return { ...o, kind: "city" as const };
});

const union = type([type1, "|", type2]);
const result = union({ age: 12, kind: "city" });
console.log(result.summary);

const type1 = type({ name: "string", age: "number", "+": "delete" }).pipe(
  (o) => {
    return { ...o, kind: "person" as const };
  }
);
const type2 = type({ city: "string", "+": "delete" }).pipe((o) => {
  return { ...o, kind: "city" as const };
});

const union = type([type1, "|", type2]);
const result = union({ age: 12, kind: "city" });
console.log(result.summary);

66 replies

Aarktype

•Created by aabad_ankit on 9/4/2024 in #questions

Can I add a default value to a type if everything other satisfies in a union type

@ArkDavid How can I get better error msg for this

const type1 = type({"name": "string",age:"number"})
const type2 = type({"city": "string"})

const union = type([type1,"|",type2])
const result = union({"age":12})
console.log(result.summary)

const type1 = type({"name": "string",age:"number"})
const type2 = type({"city": "string"})

const union = type([type1,"|",type2])
const result = union({"age":12})
console.log(result.summary)

prints "name must be a string (was missing) or city must be a string (was missing)" since age is already there shouldn't it just say "name must be a string (was missing) "

66 replies

Aarktype

•Created by aabad_ankit on 9/4/2024 in #questions

Can I add a default value to a type if everything other satisfies in a union type

docs will certainly help.

66 replies

Aarktype

•Created by aabad_ankit on 9/4/2024 in #questions

Can I add a default value to a type if everything other satisfies in a union type

I need to learn a lot 🙂 . This library is just awesome.

66 replies

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