vj_25 Comments - Answer Overflow

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vj_25

•Created by hardcoreisdead on 10/14/2024 in #💭│doubts

rotational 2

take length between p and origin as y and q and origin as x so x^2 + y^2=1 and then take derivative wrt time

21 replies

•Created by hardcoreisdead on 10/14/2024 in #💭│doubts

rotational 2

u could also try by differentiation

21 replies

•Created by vj_25 on 9/26/2024 in #💭│doubts

chem equilibrium

+solved @Real potato

9 replies

•Created by hardcoreisdead on 9/26/2024 in #💭│doubts

MOI

yes

24 replies

•Created by hardcoreisdead on 9/26/2024 in #💭│doubts

MOI

but haan har case me centroidal to ml^2/6 hi hoga

24 replies

•Created by hardcoreisdead on 9/26/2024 in #💭│doubts

MOI

woh depend karta hai tumne kya axis lia hai since its square lamina is 2d

24 replies

•Created by hardcoreisdead on 9/26/2024 in #💭│doubts

MOI

that will give ml^2/12 but it would be of half

24 replies

•Created by hardcoreisdead on 9/26/2024 in #💭│doubts

MOI

u can find mi of square plate by taking an element at a distance x from centroidal axis of length l and breadth dx and then take range of l from 0 to l/2

24 replies

•Created by hardcoreisdead on 9/26/2024 in #💭│doubts

MOI

if what ive found out is correct

24 replies

•Created by hardcoreisdead on 9/26/2024 in #💭│doubts

MOI

ml^2/12 tab aaega jab woh same side ke plate ka half karde

24 replies

•Created by hardcoreisdead on 9/26/2024 in #💭│doubts

MOI

i think ur right but the mi of square plate is coming out to me ml^2/6

24 replies

•Created by vj_25 on 9/26/2024 in #💭│doubts

chem equilibrium

accha np...thanks

9 replies

•Created by hardcoreisdead on 9/25/2024 in #💭│doubts

COM

write momentum of each particle in vector form before and after collision and assume vel of d to be v

8 replies

•Created by hardcoreisdead on 9/25/2024 in #💭│doubts

COM

u can do this by conservation of momentuv

8 replies

•Created by vj_25 on 9/26/2024 in #💭│doubts

chem equilibrium

yes

9 replies

•Created by hardcoreisdead on 8/15/2024 in #💭│doubts

wpe

u will first need to check whether the force is conservative or not by taking partial derivative of force and by doing that we see that it is not conservative so we will have to find out work done by taking separate cases..so for part a u will have to find out work done in paths OA+AB+BC by integration of F.dr

13 replies