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Shane

•Created by Shane on 7/1/2023 in #djs-questions

Fetch an array of message IDs at once

Is there some sort of way to fetch multiple messages by id in a single request? Kind of like message.channel.messages.fetch([snowflake_one, snowflake_two]) I tried interaction.channel.messages.fetch([1124766378705027212,1124766519826587670]).then(_ => console.log(_.size)) And it reports 50, which is a lot more than two lol I basically create an array full of message ids, and I want to fetch them to get their content, author id, and displayname But just running messages.fetch(id) for each one is very slow This is what I've got right now, which is works, but is undesirable as it's very slow (many times slower requesting 3 specific IDs vs limit of 3)

// Fetch references from pins
let references = await Promise.all(pins.map(p => p.reference && message.channel.messages.fetch(p.reference.messageId)))
// Insert references before the relevant pin (working backwards to prevent indexes moving)
for (let i = pins.length - 1; i >= 0; i--)
    if(references[i]) pins.splice(i, 0, references[i])

// Fetch references from pins
let references = await Promise.all(pins.map(p => p.reference && message.channel.messages.fetch(p.reference.messageId)))
// Insert references before the relevant pin (working backwards to prevent indexes moving)
for (let i = pins.length - 1; i >= 0; i--)
    if(references[i]) pins.splice(i, 0, references[i])

It just turns an array of pins, into an array of pins and whatever they're replying to I've read MessageManager.fetch(), but I don't really see what I'm looking for Despite it saying that it accepts an array of options, and individual options can be snowflakes

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