SirLancelotDuLac
IiTeachChem
•Created by Opt on 4/3/2025 in #💭│doubts
Last minute chem doubts
In melting point as far as I remember (not sure so take with a grain of salt) it depends on symmetry/packing, dipole moment, van der waal interactions and H-bonding.
19 replies
IiTeachChem
•Created by flower on 4/2/2025 in #💭│doubts
WPE
That is the work done by friction on the system however ig.
197 replies
IiTeachChem
•Created by flower on 4/2/2025 in #💭│doubts
WPE
From momenta conservation, we have m.v=4mv' meaning v'=0.25v. Now change in energy of block is w.d. by friction, so 1/2mv^2(1/16-1)=-15/32mv^2
197 replies
IiTeachChem
•Created by hardcoreisdead on 4/2/2025 in #💭│doubts
pnc
There could be a better method though ig...
13 replies
IiTeachChem
•Created by hardcoreisdead on 4/2/2025 in #💭│doubts
pnc
If you are comfortable with multinomial, this is coeffecient of x¹⁵ in (x²+x³+...+x⁹)(1+x+x²+...+x⁹)² ig.
13 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
NLM doubt - Q74 (red is key answer)
Ah, what I meant was "incomplete vector", my bad.
62 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
NLM doubt - Q74 (red is key answer)
Here we are missing one of the component of the original vector so taking the new vectors components does not give us the original vector tho.
62 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
NLM doubt - Q74 (red is key answer)
We can't.
62 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
NLM doubt - Q74 (red is key answer)
Nah man, I was doing the same error for 30 continous minutes 😭
62 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
NLM doubt - Q74 (red is key answer)
u/2 thing is itself a component and component ke components we can't take.
62 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
NLM doubt - Q74 (red is key answer)
I mean, what I said was a bit crass, I apologize. If there is no component of velocity along the incline, meaning the velocity would just be u/2 in the perpendicular direction. Now look at the other wedge and the cylinder. They must always be in contact but our assumption of no perpendicular velocity tells us the block is only moving away from the incline.
62 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
NLM doubt - Q74 (red is key answer)
'Cuz even if there is no velocity in that direction, v would come out to be zero for given constraints.
62 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
NLM doubt - Q74 (red is key answer)
Well, assuming doesn't do any harm tho right? 🥲
62 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
NLM doubt - Q74 (red is key answer)
Assume for a moment there is no such component. Then the sphere remains sort of "stuck" on the left cylinder.
62 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
SHM - Q74 (red is key answer)
Force on the mass m is -3k(4x/3) (because both springs push in the same direction) So from this we can find time period. (Also to notice, x is inversely proportional to m and x is inversely proportional to k, so mass proportional to k and m/k is constant meaning you would get the same time period for the 3m mass)
18 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
SHM - Q74 (red is key answer)
Answer comes out to be 1 ig.
18 replies
IiTeachChem
•Created by Opt on 4/2/2025 in #💭│doubts
NLM doubt - Q74 (red is key answer)
Velocity.
62 replies