duckkitarian
IiTeachChem
•Created by Parth on 10/18/2024 in #💭│doubts
NEWTON LAWS OF MOTION
Itna likhna kuch matlab nhi hua 😭
35 replies
IiTeachChem
•Created by Parth on 10/18/2024 in #💭│doubts
NEWTON LAWS OF MOTION
@nermal yaha se slowmow hata do
35 replies
IiTeachChem
•Created by Parth on 10/18/2024 in #💭│doubts
NEWTON LAWS OF MOTION
See the diagram
35 replies
IiTeachChem
•Created by Parth on 10/18/2024 in #💭│doubts
NEWTON LAWS OF MOTION
this might be totally wrong
35 replies
IiTeachChem
•Created by Parth on 10/18/2024 in #💭│doubts
NEWTON LAWS OF MOTION
Is ques mein ek pulley system ka acceleration nikalne ka solution dikhaya gaya hai. Main tumhein step-by-step samjhata hoon:
1. Equation for Force and Tension: Diagram mein ek pulley hai jis me e block se connected hai Pulley ko force (F) lagayi ja rahi hai
Yahan likha hai: 2T=F Yeh isliye hai kyunki pulley ke dono sides par strings hain aur dono sides ka tension (T) mila kar total force F hoti hai. Yeh mass ki wajah se hai, gravitational force ki wajah se nahi.
2. Tension aur Block ka Acceleration: Uske baad tension T ko block ke acceleration se relate kiya gaya hai: T = m.a(block) Matlab tension block ke mass aur uske acceleration ke proportional hoti hai. Phir block ka acceleration nikalne ke liye formula likha gaya hai: a(block)= F/2m
3. Pulley ka Acceleration: Ab pulley ka acceleration (a(pully) ) nikalna hai. Uske liye pulley ke sides ka tension aur block ka acceleration dono consider kiya gaya:
a(pully).2T = a(block).T
Simplifying karke result aaya: a(pully)= a(block)/2 Matlab pulley ka acceleration block ke acceleration ka half hota hai.
Phir aakhir mein pulley ka acceleration F aur m ke terms mein likha gaya: F/4m
35 replies