22 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.duckkitarian cooking the most detailed answer
Is ques mein ek pulley system ka acceleration nikalne ka solution dikhaya gaya hai. Main tumhein step-by-step samjhata hoon:
1. Equation for Force and Tension: Diagram mein ek pulley hai jis me e block se connected hai Pulley ko force (F) lagayi ja rahi hai
Yahan likha hai: 2T=F Yeh isliye hai kyunki pulley ke dono sides par strings hain aur dono sides ka tension (T) mila kar total force F hoti hai. Yeh mass ki wajah se hai, gravitational force ki wajah se nahi.
2. Tension aur Block ka Acceleration: Uske baad tension T ko block ke acceleration se relate kiya gaya hai: T = m.a(block) Matlab tension block ke mass aur uske acceleration ke proportional hoti hai. Phir block ka acceleration nikalne ke liye formula likha gaya hai: a(block)= F/2m
3. Pulley ka Acceleration: Ab pulley ka acceleration (a(pully) ) nikalna hai. Uske liye pulley ke sides ka tension aur block ka acceleration dono consider kiya gaya:
a(pully).2T = a(block).T
Simplifying karke result aaya: a(pully)= a(block)/2 Matlab pulley ka acceleration block ke acceleration ka half hota hai.
Phir aakhir mein pulley ka acceleration F aur m ke terms mein likha gaya: F/4m
this might be totally wrong
ye 2m kyu ayega
@duckkitarian
ammmaaa
devre thande dayanide
See the diagram
Arrows +- kr
@nermal yaha se slowmow hata do
okay
maine coaching me ek question kia tha
done
usme i used m
and sir said its correct
confused for this one tho
C
What is F
Because, one force is split among two strings.
Making necessary assumptions, it means that one-half of the total force will be responsible for the motion of the block.
Therefore,
T=ma
Where
m=mass of block
a= acceleration of block.
And T=F/2
Therefore,
ma=F/2
a=F/2m
Good boy
Itna likhna kuch matlab nhi hua ðŸ˜
yo no spam on doubts please. lets keep things focused on doubts
and slow mode stays on, think before you post, this is not for conversations but for doubt resolution :D
convos can be had on dms/other channels
+solved
+solved @iTeachChem
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