N
Nuxt2w ago
bnason

NuxtPage default page

Is it possible to define the "default" page within a page in the app/pages folder and also have a <NuxtPage /> to render children? I don't want to create a bunch of index.vue files in the children folders
11 Replies
kapa.ai
kapa.ai2w ago
Hi @bnason. I'm kapa.ai, your friendly support bot. I will try to answer your question by searching through the knowledge base. :wave: ---------------------- Yes, it is possible to define a "default" page within a page in the pages folder and also have a <NuxtPage /> to render children without creating multiple index.vue files in child folders. This can be achieved using Nuxt's nested routing feature and catch-all routes. Here's how you can implement this: 1. Create a parent page file (e.g., pages/parent.vue) that will serve as the "default" page and also include the <NuxtPage /> component to render child routes. 2. Use a catch-all route file (e.g., pages/parent/[...slug].vue) to handle all child routes. Here's an example of how your file structure and code might look:
pages/
parent.vue
parent/
[...slug].vue
pages/
parent.vue
parent/
[...slug].vue
In pages/parent.vue:
<template>
<div>
<h1>Parent Page (Default Content)</h1>
<!-- Your default content here -->

<!-- Render child routes -->
<NuxtPage />
</div>
</template>
<template>
<div>
<h1>Parent Page (Default Content)</h1>
<!-- Your default content here -->

<!-- Render child routes -->
<NuxtPage />
</div>
</template>
In pages/parent/[...slug].vue:
<template>
<div>
<h2>Child Page</h2>
<!-- Content for child routes -->
</div>
</template>

<script setup>
const route = useRoute()
console.log(route.params.slug) // Access the dynamic part of the route
</script>
<template>
<div>
<h2>Child Page</h2>
<!-- Content for child routes -->
</div>
</template>

<script setup>
const route = useRoute()
console.log(route.params.slug) // Access the dynamic part of the route
</script>
With this setup: - /parent will render the content in parent.vue - /parent/child1, /parent/child2, etc., will render the content in [...slug].vue inside the parent.vue layout This approach allows you to have a default page content and still render child routes without creating multiple index.vue files in child folders. Nuxt 3 Docs: Catch-all Route (https://nuxt.com/docs/guide/directory-structure/pages#catch-all-route) Nuxt 3 Docs: Nested Routes (https://nuxt.com/docs/getting-started/routing#nested-routes) Remember that the exact implementation might vary depending on your specific requirements and the structure of your application. ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2w ago
<@712351223482810390> Kapa.ai is still learning and improving, please let me know how I did by reacting below.
bnason
bnasonOP2w ago
@kapa.ai I do not want the default page to also be rendered with the child page
kapa.ai
kapa.ai2w ago
Let me check the knowledge base for you again. One moment! :books: ---------------------- I understand you don't want the default page content to be rendered along with the child page content. We can modify the previous approach to achieve this. Here's how you can separate the default page content from the child pages: 1. Create a parent page file (e.g., pages/parent.vue) that will only contain the <NuxtPage /> component. 2. Create an index file (e.g., pages/parent/index.vue) for the default content. 3. Use a catch-all route file (e.g., pages/parent/[...slug].vue) to handle all child routes. Here's an example of how your file structure and code might look:
pages/
parent.vue
parent/
index.vue
[...slug].vue
pages/
parent.vue
parent/
index.vue
[...slug].vue
In pages/parent.vue:
<template>
<NuxtPage />
</template>
<template>
<NuxtPage />
</template>
In pages/parent/index.vue:
<template>
<div>
<h1>Parent Page (Default Content)</h1>
<!-- Your default content here -->
</div>
</template>
<template>
<div>
<h1>Parent Page (Default Content)</h1>
<!-- Your default content here -->
</div>
</template>
In pages/parent/[...slug].vue:
<template>
<div>
<h2>Child Page</h2>
<!-- Content for child routes -->
</div>
</template>

<script setup>
const route = useRoute()
console.log(route.params.slug) // Access the dynamic part of the route
</script>
<template>
<div>
<h2>Child Page</h2>
<!-- Content for child routes -->
</div>
</template>

<script setup>
const route = useRoute()
console.log(route.params.slug) // Access the dynamic part of the route
</script>
With this setup: - /parent will render the content in parent/index.vue - /parent/child1, /parent/child2, etc., will render the content in [...slug].vue without including the default page content This approach allows you to have a separate default page content and render child routes independently, without creating multiple index.vue files in child folders. Nuxt 3 Docs: Nested Routes (https://nuxt.com/docs/getting-started/routing#nested-routes) Nuxt 3 Docs: Catch-all Route (https://nuxt.com/docs/guide/directory-structure/pages#catch-all-route) This solution should meet your requirement of not rendering the default page content along with the child pages. ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2w ago
<@712351223482810390> Kapa.ai is still learning and improving, please let me know how I did by reacting below.
bnason
bnasonOP2w ago
@kapa.ai that uses an index.vue which I don't want to have to create
kapa.ai
kapa.ai2w ago
Let me check the knowledge base for you again. One moment! :books: ---------------------- I apologize for the misunderstanding. You're right, and I see that you want to avoid creating index.vue files. Let's adjust the approach to meet your specific needs without using an index.vue file. Here's a solution that doesn't require an index.vue file: 1. Create a single file in the pages directory (e.g., pages/parent.vue). 2. Use a conditional rendering approach within this file. Here's how you can implement this:
<template>
<div>
<template v-if="!route.params.slug">
<h1>Parent Page (Default Content)</h1>
<!-- Your default content here -->
</template>
<template v-else>
<NuxtPage />
</template>
</div>
</template>

<script setup>
const route = useRoute()
</script>
<template>
<div>
<template v-if="!route.params.slug">
<h1>Parent Page (Default Content)</h1>
<!-- Your default content here -->
</template>
<template v-else>
<NuxtPage />
</template>
</div>
</template>

<script setup>
const route = useRoute()
</script>
In this setup: - When accessing /parent, the default content will be displayed. - For any child route like /parent/child1, the <NuxtPage /> component will render the content of the child page. To handle the child routes, you can create a catch-all route file:
pages/
parent.vue
parent/
[...slug].vue
pages/
parent.vue
parent/
[...slug].vue
In pages/parent/[...slug].vue:
<template>
<div>
<h2>Child Page</h2>
<!-- Content for child routes -->
</div>
</template>

<script setup>
const route = useRoute()
console.log(route.params.slug) // Access the dynamic part of the route
</script>
<template>
<div>
<h2>Child Page</h2>
<!-- Content for child routes -->
</div>
</template>

<script setup>
const route = useRoute()
console.log(route.params.slug) // Access the dynamic part of the route
</script>
This approach allows you to: 1. Have a default page content without creating an index.vue file. 2. Render child routes independently. 3. Avoid creating multiple index.vue files in child folders. Nuxt 3 Docs: Pages (https://nuxt.com/docs/guide/directory-structure/pages) Nuxt 3 Docs: Catch-all Route (https://nuxt.com/docs/guide/directory-structure/pages#catch-all-route) This solution should meet your requirements without the need for an index.vue file. ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2w ago
<@712351223482810390> Kapa.ai is still learning and improving, please let me know how I did by reacting below.
bnason
bnasonOP2w ago
@kapa.ai I ended up using <template v-if="$route.name === 'parent'"> instead of relying on a slug
kapa.ai
kapa.ai2w ago
Let me check the knowledge base for you again. One moment! :books: ---------------------- That's a great solution! Using <template v-if="$route.name === 'parent'"> is indeed a clean and effective way to conditionally render content based on the route name without relying on a slug. This approach aligns well with Nuxt's routing system and provides a clear distinction between the parent and child routes. Here's how your implementation might look:
<template>
<div>
<template v-if="$route.name === 'parent'">
<h1>Parent Page (Default Content)</h1>
<!-- Your default content here -->
</template>
<template v-else>
<NuxtPage />
</template>
</div>
</template>
<template>
<div>
<template v-if="$route.name === 'parent'">
<h1>Parent Page (Default Content)</h1>
<!-- Your default content here -->
</template>
<template v-else>
<NuxtPage />
</template>
</div>
</template>
This solution offers several advantages: 1. It doesn't require creating an index.vue file, which was one of your initial requirements. 2. It's more explicit and less prone to errors compared to checking for the presence of a slug. 3. It works well with Nuxt's automatic route naming convention. The $route object is available in the template, allowing you to access route information directly, as mentioned in the Nuxt 3 documentation on useRoute (https://nuxt.com/docs/api/composables/use-route#api). Your approach is a good example of leveraging Nuxt's routing capabilities to create a flexible and maintainable page structure. Well done on finding a solution that fits your specific needs! ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2w ago
<@712351223482810390> Kapa.ai is still learning and improving, please let me know how I did by reacting below.
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