Sapphire - Imagine a framework•2y ago

APIInteractionDataResolvedGuildMember does not have id

While fetching for member using interaction.options.getMember('member') it gives two types - GuildMember|APIInteractionDataResolvedGuildMember out of which the second one literally doesn't have member's snowflake ID I saw this https://discord-api-types.dev/api/discord-api-types-v10/interface/APIInteractionDataResolvedGuildMember and confirmed that it really doesn't have id field How am I supposed to fetch such a member (basically type guard the member)? My package.json

 "dependencies": {
    "@sapphire/decorators": "^6.0.0",
    "@sapphire/discord.js-utilities": "6.0.4",
    "@sapphire/framework": "^4.2.2",
    "@sapphire/pieces": "^3.6.1",
    "@sapphire/plugin-logger": "^3.0.1",
    "@sapphire/plugin-subcommands": "^4.0.0",
    "@sapphire/utilities": "^3.11.0",
    "colorette": "^2.0.19",
    "discord-api-types": "^0.37.36",
    "discord.js": "^14.8.0",
    "firebase-admin": "^11.5.0",
    "yaspr": "^1.0.2"
  },

 "dependencies": {
    "@sapphire/decorators": "^6.0.0",
    "@sapphire/discord.js-utilities": "6.0.4",
    "@sapphire/framework": "^4.2.2",
    "@sapphire/pieces": "^3.6.1",
    "@sapphire/plugin-logger": "^3.0.1",
    "@sapphire/plugin-subcommands": "^4.0.0",
    "@sapphire/utilities": "^3.11.0",
    "colorette": "^2.0.19",
    "discord-api-types": "^0.37.36",
    "discord.js": "^14.8.0",
    "firebase-admin": "^11.5.0",
    "yaspr": "^1.0.2"
  },

2 Replies

MRDGH2821OP•2y ago

I could definitely do this -

  const member = interaction.options.getMember('member') as GuildMember;

  const member = interaction.options.getMember('member') as GuildMember;

But I want to keep this as last resort.

Favna•2y ago

function isGuildMember(data: GuildMember | APIInteractionDataResolvedGuildMember): data is GuildMember {
  return data instanceof GuildMember;
}

function isGuildMember(data: GuildMember | APIInteractionDataResolvedGuildMember): data is GuildMember {
  return data instanceof GuildMember;
}

const member = interaction.options.getMember('member');

if (!isGuildMember(member)) {
  throw new Error('....');
}

// now it's a GuildMember, alternatively flip the if statement and keep it in inside the if statement

const member = interaction.options.getMember('member');

if (!isGuildMember(member)) {
  throw new Error('....');
}

// now it's a GuildMember, alternatively flip the if statement and keep it in inside the if statement

Gaming

Programming

APIInteractionDataResolvedGuildMember does not have id