psinfinity
IiTeachChem
•Created by Keshav on 4/16/2024 in #💭│doubts
RBD
they've taken moment of inertia about point of rotation, and KE of that point is 0.
if you were to use translational KE of COM, you'd be calculating rotational KE about COM as well, and that happens to give the correct answer as well (i checked)
11 replies
IiTeachChem
•Created by Weirdo on 4/13/2024 in #💭│doubts
Basic AOD
true, i always lose marks in such questions 💀
to stay safe, drawing graphs for every function might be best, and in maxima minima questions, checking the values at the ends of the domain
baaki sab depends on your luck 😆 and practice
24 replies
IiTeachChem
•Created by Weirdo on 4/13/2024 in #💭│doubts
Basic AOD
nvm my bad, i took local maxima, global maxima would be pi itself
f(pi) > f(pi/3)
24 replies
IiTeachChem
•Created by Weirdo on 4/13/2024 in #💭│doubts
Basic AOD
is the question wrong? i end up getting pi/3 + rt3/2 as the maxima
24 replies
IiTeachChem
•Created by Maven on 4/11/2024 in #💭│doubts
How to approach this...?
what do you mean? thats what the question is asking for
57 replies
IiTeachChem
•Created by Maven on 4/11/2024 in #💭│doubts
How to approach this...?
thats why we found 2 equations to check
overall it should be A
57 replies
IiTeachChem
•Created by Maven on 4/11/2024 in #💭│doubts
How to approach this...?
no problem 🫂
57 replies
IiTeachChem
•Created by Maven on 4/11/2024 in #💭│doubts
How to approach this...?
the point of this was to bring C(x) + D(x) in terms of x(g(x))
because in equation 3 we had xA(x) + xB(x)
overall, C(x) + D(x) is also a polynomial, but if C(0) + D(0) = 0, that would mean that constant of C(x) + D(x) = 0. So, i was able to take x common.
this was a random thought that came to mind that helped solve the question, im not sure if there's a more orthodox way @Vish maybe enlighten me 🥺
57 replies
IiTeachChem
•Created by Maven on 4/11/2024 in #💭│doubts
How to approach this...?
rip slowmode
A(x) + 2B(x) = [x^2 + 1]*[C(x) - D(x)]/2
which means that the function A(x) + 2B(x) is divisible by x^2 + 1
57 replies
IiTeachChem
•Created by Maven on 4/11/2024 in #💭│doubts
How to approach this...?
the prefactoral terms of A(x) and B(x) would simplify a bit
Using the two equations you can prove that A(x) and B(x) are in forms of [x^2+1]f(x)
would you like me to attach a solution? or do you want to solve it yourself
57 replies
IiTeachChem
•Created by Maven on 4/11/2024 in #💭│doubts
How to approach this...?
try adding and subtracting the two equations
57 replies