se5a
se5a
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CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
Ah, yeah that makes sense. Thanks
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
Though I'm still not 100% sure exactly why that is the case, without doing a bunch of research
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
I figured it was somethig along those lines.
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
you've said it's not. you've not really stated why it's not.
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
I'm using double. I expected 1+double.epsilon would not equate to 1. which is why I used double.epsilon
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
higher precision, slower, lower upper and lower bounds iirc
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
doubles are close enough. I just want to change eccentricity enough that I'm no longer dealing with parabola
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
now I gtg for a couple of min lol
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
I want precise operations. I don't want a parabolic orbit. because thats a third set of keplerian funtions. I want a hyperbolic orbit, where eccentricity is the smallest amount possible larger than 1 if the case ever arises that eccentricity IS 1.
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
if e is 1 I want to add the smalest amount possible so it's not 1
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
if(e==1){e += double.Epsolon;} 
if(e==1){//this is *still* true}
if(e==1){e += double.Epsolon;} 
if(e==1){//this is *still* true}
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
because that's the classic answer for the reverse of my problem.
54 replies
CC#
Created by se5a on 9/24/2023 in #help
❔ if(e == 1){e += double.Epsilon;}
I think you missunderstand. I don't want e to = 1
54 replies