Marvee Amasi Posts - Answer Overflow

Marvee Amasi

•Created by Marvee Amasi on 5/13/2024 in #middleware-and-os

disturbing issue I'm having with LinkedList in C language, when I count how many nodes should be

Hello world!! @Middleware & OS There is this disturbing issue I'm having with LinkedList in C language, when I count how many nodes should be in the list, I always get 1

LL count: 1

LL count: 1

Here is the relevant code to get the last element , to add, and to count

void addLL(LL * head)
{
LL *newNode;
LL *tail = getLastNode(head);

newNode = malloc(sizeof(LL));
if(newNode != DEF_NULL)
{
    newNode->ID=-1;
    newNode->TCB=-1;
    newNode->next = DEF_NULL;

    if(!head) head = newNode;
    else tail->next = newNode;      
}   
}

LL * getLastNode(LL * head)
{
    LL *temp = head;
    while(temp->next != DEF_NULL)
    {
        temp = temp->next;
    }
    return temp;
}

CPU_INT32U countLL(LL * head)
CPU_INT32U countLL(LL * head)
{
    CPU_INT32U elements = 0;
    LL * temp = head;
    while(temp->next != DEF_NULL)
    {
        temp = temp->next;
        elements++;
    }
    return elements;
}

void addLL(LL * head)
{
LL *newNode;
LL *tail = getLastNode(head);

newNode = malloc(sizeof(LL));
if(newNode != DEF_NULL)
{
    newNode->ID=-1;
    newNode->TCB=-1;
    newNode->next = DEF_NULL;

    if(!head) head = newNode;
    else tail->next = newNode;      
}   
}

LL * getLastNode(LL * head)
{
    LL *temp = head;
    while(temp->next != DEF_NULL)
    {
        temp = temp->next;
    }
    return temp;
}

CPU_INT32U countLL(LL * head)
CPU_INT32U countLL(LL * head)
{
    CPU_INT32U elements = 0;
    LL * temp = head;
    while(temp->next != DEF_NULL)
    {
        temp = temp->next;
        elements++;
    }
    return elements;
}

So here is how I call the function :

LL* list;

addLL(list);
int count = countLL(list);
Debug_LOG("LL count: %i", count);

LL* list;

addLL(list);
int count = countLL(list);
Debug_LOG("LL count: %i", count);

Please help me spot where I went wrong?

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