13 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.wut the heil i mean
this is not good
??
like rho1 > rho 2 but h1<h2
how can we answer it with like full that yea P1 < or > P2
same goes for F1 F2
i wouldnt really prefer usin h1<h2 since its not mentioned in ques but given in fig
bhai agar question me use nahi karna hota to phir wo h1 h2 alag kyu dete
i hate such questions
its a gamble
but ha if we dont consider h1 h2 to be diffrent then P1 will be greater and so will F1
One nice way to look at the pressure wala point is: The area is increasing with height, so, if on adding the same volume of a liquid, the height increases more slowly at higher height. So, in container 2, height can't componsate for lesser density and hence pressure at bottom is lower.
Ye wala hogya ky!?
rho1 v1=rho2 v2
and p=rho g h can be written as rho g v/A constant
in this case we can simplify this further since rho v = m
mg/A=p now the one with bigger area should have less pressure since rest is constant note that area is proportional to height in the case of cone thus the one with more height should have less pressure
very interesting take. nicely done
idts we can write P=rho g h = rho g V/A
V represents volume of a frustum and not a cylinder
ans is A,D btw