11 Replies
@Dexter
Note for OP
+solved @user1 @user2...
to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
,rotate

Ig the energy is equal to h*v/lambda thing is incorrect.
It would be h/mv=lambda_p and then (mv^2/2):hc/(h/mv)=v:2c=c/4:2c=1:8
can u explain why
I don't think kinetic energy of electron can be given by h nu
That's something called Compton frequency etc.
Ke is always 1/2 mv2 (for non zero mass things lol]
OMG I CANT READ I SOLVED IT THINKING IT READ PROTON
BRUH
i think you wrote the expression for energy wrong shouldnt it be like K.E electron= h^2/2lambda^2 Me
and photon energy is just hc/lambda

For massive (having mass) bodies, kinetic energy is p²/2m
For non massive bodies, ie, quanta/photons, it's pc = h(nu)