De broglie λ

What's the mistake in my sol.?
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13 Replies
iTeachChem Helper
@Dexter
iTeachChem Helper
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
Say_miracle_shadow
Say_miracle_shadowOP2mo ago
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Say_miracle_shadow
Say_miracle_shadowOP2mo ago
,rotate
TeXit
TeXit2mo ago
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SirLancelotDuLac
Ig the energy is equal to h*v/lambda thing is incorrect. It would be h/mv=lambda_p and then (mv^2/2):hc/(h/mv)=v:2c=c/4:2c=1:8
hardcoreisdead
hardcoreisdead2mo ago
can u explain why
iTeachChem
iTeachChem2mo ago
I don't think kinetic energy of electron can be given by h nu That's something called Compton frequency etc. Ke is always 1/2 mv2 (for non zero mass things lol]
727
7272mo ago
OMG I CANT READ I SOLVED IT THINKING IT READ PROTON BRUH i think you wrote the expression for energy wrong shouldnt it be like K.E electron= h^2/2lambda^2 Me and photon energy is just hc/lambda
727
7272mo ago
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Opt
Opt2mo ago
For massive (having mass) bodies, kinetic energy is p²/2m For non massive bodies, ie, quanta/photons, it's pc = h(nu)
Say_miracle_shadow
+solved @Opt @727 @SirLancelotDuLac
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