Chemical equilibrium, finding equilibrium constant

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@Dexter
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Nimboi [ping if answering]
i dont understand that equation they gave what info are they trying to give?
Opt
Opt3w ago
Take it as A +B → C+D They've given -d[A]/dt = x[A]-y[B] Basically. Which is nothing but a way to give you kf and kb
Nimboi [ping if answering]
oh how come?
Opt
Opt3w ago
Because one is rate constant for forward reaction and one is rate constant for backward x and y that is
Nimboi [ping if answering]
so what they're saying is rate of consumption of A = kf * how much A is left - kb * how much B is left im tryna make this feel intuitive
Opt
Opt3w ago
Yup But it's just rate of consumption of A due to forward - rate of production of A due to backward With the rate expressions plugged in
Nimboi [ping if answering]
ahhh yeah cuz rate const * conc is just rate
Opt
Opt3w ago
Mhm
Nimboi [ping if answering]
gotcha lemme try solving got it been a while since i did equilibrium how'd english go?
Opt
Opt3w ago
And if I'm not wrong, if you set it equal to zero, you should get that the concentrations should be in ratio of kf/kb because well...if dA/dt =0, that's equilibrium innit? Crappy
Nimboi [ping if answering]
yeah cuz then rate of consumption of A = rate of production of B oh? too lengthy?
Opt
Opt3w ago
Nah, I even did extra attempts.
Nimboi [ping if answering]
my issue w english apart from lengthy was that my vocabulary is just ass
Opt
Opt3w ago
It's just that paper was crappy quality
Nimboi [ping if answering]
lmao then u chilling
727
7273w ago
litrature or reading part
Nimboi [ping if answering]
2 years of science have just made me dumb at using nice words ill mark this as solved +solved @Opt
iTeachChem Helper
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