C
C#•4w ago
Faker

✅ Use of Func as part of function definition

C#
static Func<int, int> GetMultiplier(int factor)
{
    return (num) => num * factor;
}
C#
static Func<int, int> GetMultiplier(int factor)
{
    return (num) => num * factor;
}
Hello guys, I came across this function definition where we use Funct<> as part of the function definition. I'm a bit lost here, what are we doing? I know that Func<> is a delegate where we can store function references but here we aren't doing that. Oh, or may be that's because we are returning a function reference?
8 Replies
Angius
Angius•4w ago
Wym? You are returning a function that takes an int and returns an int It's not typed explicitly, but the compiler can figure it out from the return type
Faker
FakerOP•4w ago
hmm I'm confused about the Func<int,int> part; it refers to what in the code, the inner function whick takes num as parameter?
Angius
Angius•4w ago
Well, it's the return type of the GetMultiplier method That method returns a lambda/function 
static Func<int, int> GetMultiplier(int factor)
{
    Func<int, int> fun = int (int num) => num * factor;
    return fun;
}
static Func<int, int> GetMultiplier(int factor)
{
    Func<int, int> fun = int (int num) => num * factor;
    return fun;
}
Maybe this clears things up?
Faker
FakerOP•4w ago
oh wait ohh ok yeah I see makes more sense now, I didn't notice that we were using num without declare it as an int, this is what you mean by "not explicitly typed" ?
Angius
Angius•4w ago
Yeah C# is decently smart about figuring out the types on your lambdas
Faker
FakerOP•4w ago
C#
static Func<int, int> GetMultiplier(int factor)
{
    return (num) => num * factor;
}
C#
static Func<int, int> GetMultiplier(int factor)
{
    return (num) => num * factor;
}
This is possible because of Func<int,int> ?
Angius
Angius•4w ago
Yep
Faker
FakerOP•4w ago
yeah I see, it's clearer now, thanks !!

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