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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.The answer is 0.07
Molarity of BaOH * Volume of BaOH * nFactor of BaOh = Molarity of HCl * Vol. of HCl * nFactor of HCl
humare sir ne bataya hai ki aise questions me seedha seedha equivalents equate karna hota hai (and it makes sense as well as for why we would do this)
But what is 35 ml here ?
It's written titre value
thats the volume of hydrochloric acid used
yea cuz thats te value you get during titration in the tirarnt if i remeber correctly
have you done practicals for this??
Not for this one
thats why :p
And I don't remember
search up titration on YT
its very cool
and fun
to do and watch
Is titre value not after titration and HCl is used before titration
no lol
So please explain completely
its given no on titration with HCl acid
its given that
the Barium Hydroxide solution is titrated with an HCl acid ka solution right
no where is it mentioning that it is reacted beforehand or smthing
Yeap and gives a titre value of 35 ml
all the reacting is taking place during titration
and during that
the volume of HCl which we ended up using
to complete react the solution of Barium is 35 mL
one sec
Oh I think there is some sort of confusion in titration process only
yea wait wait
now see
in this setup no
we will have the Barium solution as the titrand
and HCl as Titrant
Oh I thought titrand as titrant
Yeah
we drop by drop release the HCl solution into the Barium soln
Yeah now I remember
lol ye galti maine practical me kari thi
yea
So why did we use normality here and not molarity?
i dont see how we would use molarity here
My one more doubt is this like where to use molarity and where to use normality?
what i like doing is analysing whats given in Q
like for eg
if Q me im only given Molar Mass an volume and just one solution is mentioned id find out clues and figure out Molarity
if reaction ki baat ho rahi
id think about normality and equivalents
titre value is the vol of HCl ?
cuz Molarity dont really help in figuring out how much of a reagent we used
thats the only possible explanation and it gave the answer too
i see
Titre value is the volume of a solution used in a titration to reach the endpoint.
Google baba
so yea it pretty much clicks in automatcally after you do a bunch of questions
ight i have forgotten the lab terms 💀
good reminder lul
me too lol
Have you given your jee?
i havent lol mai to 11th me hu
Oh ok
yea
So from where do you study?
Coaching join kari hai maine (jinki management is shit)
but yea im making it work
Oh ok
yups
ngl online lectures >
Where do we use molarity then ?
Is it for acid base we use normality? And for others molarity?
MxNxV
Molarity bhai jaha par bhi aapko compound ka Molar Mass, weight volume aisa sab diya ho tab aap Molarity ke baare me socho
theres only 2 types of titrations and maine sirf ek hi padha hai Acid Base wala but i dont think ki straight up sirf Molarity ka use karke we can calculate everything about Titration
n is n factor
we always equate normals
and its legit the best thing for redox
legit bro har question me bas normals equate kar do ya phir equivalents equate kar do
For Acid base titration things nah ? Or for every question
pretty much every question
i mean thats how this formula came to be lol
keyword: pretty much
kuch questions honge
jinme kuch alag lage
but wo bhi relatively easy hote hai lol
basically if YOU spot these thiings in a questions:
1. Compound (for nfactor)
2. Molarity of Compounds
3. Volumes of Compounds
4. They are reacting
Normality/Equivalents Equate kar do
Can we use normality in this 29 no question too ?
yes
exactly yahi karna hai
both mai 1 hoga
Can you send me by solving it ?
wait nvm i thought ye bhi titration hai thats why i said n factor value
ignore the 1 wali statement
sure one sec
yaha par equivalents equate karenge not normality my fault
ruko im having breakfast ill write and send
OYE WAIT
NAHI
UIhfuihdishvin
ruko
maine aapke photo ke baad jo kuch bhi bola sab hold pe daalo ruko
isme n calculate karo add karo then v add karo to make molarity
bhai NaOh me hi dubara NaOH daal rahe
of diffrent concentrations
gtg for now dad calling
ill brb
Wait I will come shortly tab tak solve kardo agar normality se hora toh
yoyo got it yaha par ye sab nahi lagega
i get what you were asking earlier now
and ok i got it
n is same here toh i have used N and M interchangeably
jaha par bhi you find that diffrent compounds are reacting waha par you can use normals/equivalents but here i didnt get an approach using that
i instead what i did was ki
1. find moles of Naoh in each soln
2. find total moles
3. find total volume after mixing
4. fincal concentration = total moles/total vol.
alternative is this but this is lengthy
ohhhhhhh ncie
ohhh new shi noice
just use what i sent
yea ig you can use Normals and equivalents everywhere
damn
Normality 🙇♂️
think like number of atoms same hone chaye of titration and diltuion mai atoms add kardo
🛐
also atoms cuz n factor but i think it makes the point
clear
thats a nice way to visualise stuff
only if i could solver chem like this in exams
😭
anyways mai chala physics karne Physical Chem is not my cup of tea
us.
bro in my last test i forgot the value of R(earth) and was like i know this i wrote the formula and everything
idk why i forget constants
Hey anyone there ?
Normality is just molarity × n factor
And these type of questions are called mixing of solutions or dilution of solution
So in these type of questions we equate either
No of moles or mass
So here what are we equating?
titration is mixing like the first one and second one is dilution
and yes n factor into M is normality
the concept behind this is conservation of equivalents
basically in titration both equivalents on LHS and RHS need to be equal to reach endpoint
but in dilution the equivalents are just increased
along with volume thats why they have have different molarity
Is equivalents equal to no of moles × n factor?
equivalents is n factor into number of moles
molarity into volume gives no moles
see how that works
Yup that's what I said
mb i thought you wrote molarity into n factor mb
😭
also i think khan acadamy has a good lecure on normality id reccomend wtching one on this topic it is small
just that they teach it in like the span of 4-5 chapters so it gets pushed around
Ok
Can you share the link
Please
And also I had one more doubt which I asked earlier
@727 this doubt
https://discord.com/channels/1226379612238385242/1343986933210288203
@Phalawor
https://discord.com/channels/1226379612238385242/1343986933210288203
,rotate
Couldn't find an attached image in the last 10 messages.
So my main question is how did you know that in third part 2 products will be formed?
Is it because?
So can I do this in these questions?(no3 one)
Let's say by reading the question I start by taking a reaction let's say that c + O2 = co and here the carbon is the limiting reagent so I should have taken another equation and not this one BC of the question so this equation becomes wrong so I take the second equation of co2 one and here the limiting reagent is oxygen so the product should be co not co2 but I took CO2 so this equation also becomes wrong so that means if both equation becomes wrong than in that case can I assume that both the products will be formed and not one
(And can I apply this logic to all the questions related to this topic)
?
And then by this process I will use the x and y method and solve the problem
❓❓❓❓❓❓❓❓❓❓
this guy showed how
lemme see
but frankly i dont really get your doubt 💀
just ping the alpha dwag (iteachchem)
i think he teaches chem or smth
yea fr @thunder_god1286 ask @iTeachChem sir 🙏
i legit have forgotten this stuff merko OC bhi nahi aa raha PC bhi hil gaya hai aa raha IOC thoda bahot aata hai
same 😭
I asked sir but he don't have time so he told to ask in the grp ?
So let me explain my doubt once again
So there are three sub questions right in this question so in the third one
How did you get to know that 2 products both co2 and co will be formed ?
because its like a random process
maybe collission of a carbon atom and 2 oxygen atoms and CO2 is formed
or maybe just 1 and 1 so CO
so we have to consider both
hmm using collision is neat man
nice way of thinking
u dont need to go thru each product option every time, both products could form , here u cans ee when carbon and oxygen combine the possibility of anything outsie CO and CO2 forming is extremely low- so just know the standard compounds like if it was S and O i would probably go for SO2 and SO3 because any other compound outside that is very improbable and we know these r standard stable compounds
So for solving question
Can we use this approach?
but isnt that a waste of time
trying 3 equations
in these ques it probably always means more than 1 compound being formed
But in the part 1 and 2 of this question only one compound was formed?
where can u show que
i didt read it
mayeb u r right then
oh dude
in that
its given in question itself
so u dont need to use my logic
So now
?
OH you want all the product to be CO in second case ? cuz C has more moles
is that your doubt
It's written in the question that if carbon is in excess then co will be formed and when o is in excess then co2
So in third question it's confusing you can solve and see it
So my doubt is in 3rd question how do we know that 2 products both co and co2 is formed ? Because the 1st 2 questions I solved it they were easy were only one product was formed as in those questions it was clear which is in excess and which is limiting
just do it in steps like this guy did first form CO then form CO2
but ig it's not clearing the concept so @iTeachChem please help out sir
Ok
@iTeachChem
Hope you understand now
volume of HCl used to neutralise this, HCl is in the burette. Check lab manual for how titrations work, would be there.
35 x 0.1 = 25 x (n)
n is the normality of barium hyrdoxide.
normality = n factor x molarity
so molarity is normality/2
Sorted?
Yeah I got this question
Please help me with the doubt I asked you in telegram
Others are not able to get my doubt
I also sent a picture of my doubt
This
@iTeachChem
LMAO
NAHH THATS WILD
Wdym that's the question
That's what is confusing me also
Can you close this thread out? One doubt one thread please. Post ek baar fir se along with the original question (book or photo?)
Yep let’s close this out. Start a new thread for the other doubts?
So that the students who closed this doubt get credit for it :)
iteachchem
Transcription requested by thunder_god1286
I think we discussed about this, right? If oxygen is in excess, then CO2 gets formed. If it's a limited amount, then CO gets formed. Otherwise, a mixture of those also could be formed. It depends on conditions, really. So it's not about this question in particular. In real life, you would limit it by giving it just enough oxygen to make CO or CO2. There is no case in real life where you would have to make both CO and CO2. That's a bad thing for a mixture, because separating them is a pain.
+solved @727 @Phalawor @burrito
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