SHM
The q seems easy but i cant seem to get the valid relations necessary to obtain the answer
59 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.,rotate
WHAT THA HELL IS THIS
KAHA MIL RAHA BHAI YE
KYA HAI YE
well original q toh simple tha sirf time period nikalna tha for e=1 but then sir got hyped up and made this 💀
Same question
Sir ko bolo kyu question ki khichdi kar rhe ho
😭😭
bro the teacher and us 7-8 students spent like almost 45m on this 💀
and yet we couldnt calculate ☠️
EVEN THE TEACHER DOESN'T KNOW THE ANSWER
😭😭😭
i mean thats why i came here 😭
Frrr
we somehow deduced that it mostly will take only 1 collision
but thats just cause e=1/2 is a good value to estimate the energy but i cant do for some other value of e
bro legit imagine he himself made this q and he himself couldnt solve it 💀
how am i meant to solve it? ☠️
The question is god level
☠️☠️
Tried our frind chat gpt?
,rotate
Couldn't find an attached image in the last 10 messages.
anyway
very interesting question
ima try
ive already rotated it below
aight
bro i dont wanna break chatgpt forever 💀
Frr that too
got a cosine value as nearly 4 when tryna do this
i think i should sleep and try tomorrow 🙏
😂
bro legit everyone gives up after trying to do the calculation 💀
yeah wtf is this
ill use desmos and calculators if necessary
but logic part ill try on my own
do you have like a software or smth which can project this
i dont but if you find one lemme know
actual loaded physics simulators are just shitass complicated
well partly by maths and partly by logic we somehow reached the conclusionw that it mostly takes 1 collsiion
aight
gnight lmao
but thats because e has a good value which is half
oh
aight gn
guys help
I'll try this.
What is this small angle nonsense good lord
One collision seems to work with a lot of approximation
Handwriting isn't amazing
@HydraYT @Nimboi
Pls verify 🙏
yuh yuh
oh lord
nah bro its fine
DAMN
@Opt please explain me every step im really dumb 💀
First step, i conserved energy to get the speed right before the collision
0.5mu² = mg∆h
right
continue
Then, collision.
yeah
velocity becomes half
Square on both sides
To make it easier
Get v²
And conserve energy again
yeah
oh
damn
@Opt god bro
i was trying to find it by usign eqns of SHM 💀
@Opt is there a way to solve this by angular SHM eqns?
I have no clue
btw this is mains lvl q right?
like if i just ignore info about SHM
this could be considered mains lvl right
?
um
?
ah h_max after collision is where i tripped up
seems correct very cool
i forgot the cos(theta) small angle approximation
i think as long as the approximations are upward it'll be correct
like if the real mathematical answer was 0.7 collisions, we can say its 1 collision
if the answer was 1.3 collisions, then we'd have to go 2 collisions right?
Yup
this is a bit outta my ass do verify what i just said
ah nice
I just realised.
I made a mistake
Frack
h_max will be h+(v²/2g)
wait yeah it will be mgh+1/2mv2=mghmax right
Yup.
oh f
So my answer was wrong.
It'll be greater than one degree
Wait
It'll always be greater than one degree
how
It'll always be mgh+(some small number)
right
So the pendulum will always try to go a tiny bit above the level of the slanted wall
So it'll always collide with the wall
bro
I might be spouting bs
But that's what the numbers seem to say.
yeah im understanding what you said
but just logically at some point it cant have enough energy to collide
yo i did the same thing
@Opt i will confirm soln in 2-3 days with my sir till then if you find an alternative tell me
i wanna know a method to solve this from SHM eqns
W questions ping me too when you find out
nice sol
aight