cross posting from #typescript

noob question! how would i express this type using arktype syntax?

type MyType = Record<string, unknown>[]

type MyType = Record<string, unknown>[]

i tried:

type(type.Record("string", type.unknown), "[]")

type(type.Record("string", type.unknown), "[]")

but it doesn't work on v2.0.0-rc.30.

7 Replies

ssalbdivad•3w ago

I would just chain .array() instead of using the args syntax:

type.Record("string", type.unknown).array()

type.Record("string", type.unknown).array()

What you wrote should work but it seems like a TypeScript bug It does work if you split it up though so some TS issue related to the inner inference:

const dict = type.Record("string", type.unknown)

const t = type(dict, "[]")

const dict = type.Record("string", type.unknown)

const t = type(dict, "[]")

Or this if you prefer I suppose:

const t = type({ "[string]": "unknown" }, "[]")

const t = type({ "[string]": "unknown" }, "[]")

ahrjarrettOP•3w ago

thanks for the quick response! hmm, i don't know if splitting it up is an option. let me try .array() i'm doing this programmatically, so i need to make sure i'm able to detect when to use which syntax, in which context will .array() work in all cases?

ssalbdivad•3w ago

You're generating ArkType definitions?

ahrjarrettOP•3w ago

yeah

ssalbdivad•3w ago

Yeah .array() should be the most reliable nothing can really go wrong

ahrjarrettOP•3w ago

cool, thank youuu you're the best

ssalbdivad•3w ago

As long as you avoid nested type calls or nested tuple expressions you should be pretty safe in general though Stuff like your original definition generally works but TS has weird rules around inference that can sometimes get in the way. As long as you don't have anything like that or nested tuple expressions for a similar reason all roads should lead to Rome or whatever haha

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cross posting from #typescript

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