thermo 2
Two moles of helium gas undergoes a cyclic
process as shown in the fi gure. Assuming ideal
behaviour of gas, the magnitude of net work done
by the gas in this cyclic process is
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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.work in bc is nrdelT = 200R
work in da is = -200R
confused about ab and cd
Why 200 del T= 100
Nvm I didn’t read 2 Mols
Ab and cd are 0
As del T is 0
isothermal mein work done zero thodi hota hai
i am confused whether i should take it as reverisble or irreversible
Work done is nRTlnV/v
look cyclic hai, so maybe we consider finite steps
meaning it will be irreversible
P1v1=p2V2 laga lo
V1 ko variable le ke dekh lo
-Ln2 hoga for AB
Like -nRTln2
Cd phir without negative
you cant plot irrev stuff on graph
this is reversible
thats for reversible tho
how?
I think it still works if temperature is not changing
Uhhhh
This ig
Since you can't plot irreversible the graph is of reversible
But sir why can't we plot irreversible processes
exactly
infact it should be easier to plot irreversible ones since steps are definite
What does being reversible and irreversible have to do with equilibrium??
bro if yo uplot on graph
it has to be reversible
please revise basics :) read a good book or watch my sessions
i have explained this in detail
Ok sir
you dont know the path it will take
there is no way to know
rev processes me each step is in eq
pi = pext on each step
Ohhhh in that sense
Any suggestions sir I’m also going to do thermo
ideal is read zumdahl
else watch my sessions :D
Bet
Aakash Byjus wala channel right??
I think it’s in sirs discord profile one of the links
yea, link is in bio
bento ones
ok sir
thanku
Imma pull an all nighter thermo dynamics speed run
L1 for this one btw
reversible isothermal it is. thank you
+solved @iTeachChem
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