organic
What is this formation constant?? Should it be less or high for a rxn moving forward
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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Can you please elaborate this doubt?
i suppose it refers to rate constant of formation , and it should be high for moving forward (i might be wrong)
Rate of formation/rate of backward rxn = equilibrium constant
It the value is less than equilibrium constant then forward rxn if it is greater than K then backwards rxn
Referring to que number 1
the carbocation will be most unstable in option a?
and highest in c
,rotate
this is absolutely right
Chemistry LibreTexts
19.6 Nucleophilic Addition of HCN: Cyanohydrin Formation
i suppose the one that has the most stable alkoxide form should be the highest K value
How come the ans is A then
perhaps because NO2 group is ring deactivating?
Am i getting the mechanism wrong? The carbocation will form as intermediate ig
how will a cation form samjha nahi?
this is the mechanism
carbonyl compounds me it is usually a nucleophilic attack
or protonation of the O
in this case both lol doesnt matter which one happens first.
Oh my bad
Got confused man sorry
all g
Thanks dude
+solved @iTeachChem
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