SolidJS•3mo ago

How do I run an effect every change except initialization?

I need to run an effect every subsequent change of a signal's value. I just need to skip the first initialization of the signal. I found this answer https://stackoverflow.com/a/78283918 and I implemented it, but it's not triggering on any updates.

const [value, setValue] = createSignal(props.defaultValue ?? 0);
createEffect(
  on(
    value,
    (val) => {
      console.log(val); // Should log when the value changes, but not on initialization
    },
    { defer: true },
  ),
);

const [value, setValue] = createSignal(props.defaultValue ?? 0);
createEffect(
  on(
    value,
    (val) => {
      console.log(val); // Should log when the value changes, but not on initialization
    },
    { defer: true },
  ),
);

4 Replies

mdynnl•3mo ago

this should work if not try reproducing on the playground

RATIU5OP•3mo ago

Hmmm. Can't seem to reporduce in the playground. Let me check my code again

Eve•3mo ago

yeah, you're doing something wrong somewhere, because that absolutely works.

RATIU5OP•3mo ago

You're right; my signal isn't updating elsewhere in my code. Considering this thread as solved.

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How do I run an effect every change except initialization?