C#•5mo ago

Confused on why my simple leetcode solution works

12 Replies

GreyaOP•5mo ago

lets use the first data test case 1 is listed twice so it returns true but my second loop tests for i+1. so j= i +1 right lets assume i is at number 3 in the first test case. then j (which is i+1) would be at 1 3 and 1 are not the same so why does it return true?

Angius•5mo ago

Did you use the debugger? It will let you see what each value is at any given point

GreyaOP•5mo ago

the other solutions are like this to im just confused on how its correct if i said j = i+3 then that would make sense because if i is at 1. then j would be at 1 again but i said j = i+1 so i and j should never be the same number yet it still works

Angius•5mo ago

i=0 => j=1,2,3 i=1 => j=2,3 i=2 => j=3 i=3 => j= It never compares numbers on the same position

GreyaOP•5mo ago

wait what so j

Angius•5mo ago

numbers[x] will never be compared with numbers[x]

GreyaOP•5mo ago

is all the numbers past i? not just the number infront of i

Angius•5mo ago

Well, yes, you start with a j that is one higher than i

GreyaOP•5mo ago

if i have an array {1,2,3,4,5} and i is at number 2. then j would be number 3 no? assuming j is i+1?

MODiX•5mo ago

Angius

REPL Result: Success

int[] nums = {34, 45, 56, 67};
for (var i = 0; i < nums.Length; i++)
{
    for (var j = i + 1; j < nums.Length; j++)
    {
        var even = nums[i] == nums[j];
        Console.WriteLine($"[i={i}, j={j}]: {nums[i]} == {nums[j]} => ${even}");
    }
}

int[] nums = {34, 45, 56, 67};
for (var i = 0; i < nums.Length; i++)
{
    for (var j = i + 1; j < nums.Length; j++)
    {
        var even = nums[i] == nums[j];
        Console.WriteLine($"[i={i}, j={j}]: {nums[i]} == {nums[j]} => ${even}");
    }
}

Console Output

[i=0, j=1]: 34 == 45 => $False
[i=0, j=2]: 34 == 56 => $False
[i=0, j=3]: 34 == 67 => $False
[i=1, j=2]: 45 == 56 => $False
[i=1, j=3]: 45 == 67 => $False
[i=2, j=3]: 56 == 67 => $False

[i=0, j=1]: 34 == 45 => $False
[i=0, j=2]: 34 == 56 => $False
[i=0, j=3]: 34 == 67 => $False
[i=1, j=2]: 45 == 56 => $False
[i=1, j=3]: 45 == 67 => $False
[i=2, j=3]: 56 == 67 => $False

Compile: 494.046ms | Execution: 70.268ms | React with ❌ to remove this embed.

MODiX•5mo ago

Angius

REPL Result: Success

int[] nums = {34, 45, 56, 34};
for (var i = 0; i < nums.Length; i++)
{
    for (var j = i + 1; j < nums.Length; j++)
    {
        var even = nums[i] == nums[j];
        Console.WriteLine($"[i={i}, j={j}]: {nums[i]} == {nums[j]} => ${even}");
    }
}

int[] nums = {34, 45, 56, 34};
for (var i = 0; i < nums.Length; i++)
{
    for (var j = i + 1; j < nums.Length; j++)
    {
        var even = nums[i] == nums[j];
        Console.WriteLine($"[i={i}, j={j}]: {nums[i]} == {nums[j]} => ${even}");
    }
}

Console Output

[i=0, j=1]: 34 == 45 => $False
[i=0, j=2]: 34 == 56 => $False
[i=0, j=3]: 34 == 34 => $True
[i=1, j=2]: 45 == 56 => $False
[i=1, j=3]: 45 == 34 => $False
[i=2, j=3]: 56 == 34 => $False

[i=0, j=1]: 34 == 45 => $False
[i=0, j=2]: 34 == 56 => $False
[i=0, j=3]: 34 == 34 => $True
[i=1, j=2]: 45 == 56 => $False
[i=1, j=3]: 45 == 34 => $False
[i=2, j=3]: 56 == 34 => $False

Compile: 504.328ms | Execution: 69.859ms | React with ❌ to remove this embed.

Angius•5mo ago

Ignore that $, a JS-ism found it's way in lol

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Confused on why my simple leetcode solution works

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