C#•2mo ago

Confused on why my simple leetcode solution works

12 Replies

Greya•2mo ago

lets use the first data test case 1 is listed twice so it returns true but my second loop tests for i+1. so j= i +1 right lets assume i is at number 3 in the first test case. then j (which is i+1) would be at 1 3 and 1 are not the same so why does it return true?

Angius•2mo ago

Did you use the debugger? It will let you see what each value is at any given point

Greya•2mo ago

the other solutions are like this to im just confused on how its correct if i said j = i+3 then that would make sense because if i is at 1. then j would be at 1 again but i said j = i+1 so i and j should never be the same number yet it still works

Angius•2mo ago

i=0 => j=1,2,3 i=1 => j=2,3 i=2 => j=3 i=3 => j= It never compares numbers on the same position

Greya•2mo ago

wait what so j

Angius•2mo ago

numbers[x] will never be compared with numbers[x]

Greya•2mo ago

is all the numbers past i? not just the number infront of i

Angius•2mo ago

Well, yes, you start with a j that is one higher than i

Greya•2mo ago

if i have an array {1,2,3,4,5} and i is at number 2. then j would be number 3 no? assuming j is i+1?

MODiX•2mo ago

Angius

REPL Result: Success

int[] nums = {34, 45, 56, 67};
for (var i = 0; i < nums.Length; i++)
{
    for (var j = i + 1; j < nums.Length; j++)
    {
        var even = nums[i] == nums[j];
        Console.WriteLine($"[i={i}, j={j}]: {nums[i]} == {nums[j]} => ${even}");
    }
}

int[] nums = {34, 45, 56, 67};
for (var i = 0; i < nums.Length; i++)
{
    for (var j = i + 1; j < nums.Length; j++)
    {
        var even = nums[i] == nums[j];
        Console.WriteLine($"[i={i}, j={j}]: {nums[i]} == {nums[j]} => ${even}");
    }
}

Console Output

[i=0, j=1]: 34 == 45 => $False
[i=0, j=2]: 34 == 56 => $False
[i=0, j=3]: 34 == 67 => $False
[i=1, j=2]: 45 == 56 => $False
[i=1, j=3]: 45 == 67 => $False
[i=2, j=3]: 56 == 67 => $False

[i=0, j=1]: 34 == 45 => $False
[i=0, j=2]: 34 == 56 => $False
[i=0, j=3]: 34 == 67 => $False
[i=1, j=2]: 45 == 56 => $False
[i=1, j=3]: 45 == 67 => $False
[i=2, j=3]: 56 == 67 => $False

Compile: 494.046ms | Execution: 70.268ms | React with ❌ to remove this embed.

MODiX•2mo ago

Angius

REPL Result: Success

int[] nums = {34, 45, 56, 34};
for (var i = 0; i < nums.Length; i++)
{
    for (var j = i + 1; j < nums.Length; j++)
    {
        var even = nums[i] == nums[j];
        Console.WriteLine($"[i={i}, j={j}]: {nums[i]} == {nums[j]} => ${even}");
    }
}

int[] nums = {34, 45, 56, 34};
for (var i = 0; i < nums.Length; i++)
{
    for (var j = i + 1; j < nums.Length; j++)
    {
        var even = nums[i] == nums[j];
        Console.WriteLine($"[i={i}, j={j}]: {nums[i]} == {nums[j]} => ${even}");
    }
}

Console Output

[i=0, j=1]: 34 == 45 => $False
[i=0, j=2]: 34 == 56 => $False
[i=0, j=3]: 34 == 34 => $True
[i=1, j=2]: 45 == 56 => $False
[i=1, j=3]: 45 == 34 => $False
[i=2, j=3]: 56 == 34 => $False

[i=0, j=1]: 34 == 45 => $False
[i=0, j=2]: 34 == 56 => $False
[i=0, j=3]: 34 == 34 => $True
[i=1, j=2]: 45 == 56 => $False
[i=1, j=3]: 45 == 34 => $False
[i=2, j=3]: 56 == 34 => $False

Compile: 504.328ms | Execution: 69.859ms | React with ❌ to remove this embed.

Angius•2mo ago

Ignore that $, a JS-ism found it's way in lol

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Confused on why my simple leetcode solution works