Use native ts type

I was wondering if I could use an already created type:

type BlockainsName = "bitcoin" | "ethereum" | "solana" | "polygon-pos" | "binance-smart-chain" | "avalanche"

type BlockainsName = "bitcoin" | "ethereum" | "solana" | "polygon-pos" | "binance-smart-chain" | "avalanche"

inside an arktype type declaration:

export const walletType = type({
  address: "string",
  blockchain: "BlockainsName",
  {...}

export const walletType = type({
  address: "string",
  blockchain: "BlockainsName",
  {...}

I would go on and create an arktype literal as suggested in the docs, but this type is being declared from another object:

export type BlockainsName = keyof typeof blockchains

export type BlockainsName = keyof typeof blockchains

And I want it to be tighly coupled with that object

4 Replies

TizzySaurus•4mo ago

Iirc .as can be used for using a pre-existing type

Dimava•4mo ago

const EveryBlockainsName = Object.keys(blockchains) as BlockainsName []

type(['===', ...EveryBlockainsName ])

const EveryBlockainsName = Object.keys(blockchains) as BlockainsName []

type(['===', ...EveryBlockainsName ])

ssalbdivad•4mo ago

If you have them in an object I'd do what Dimava suggests so there's a single source of truth. You can also do type.enumerated(...keys) if you prefer. You'll just have to make sure you cast your keys list since TS won't narrow it by default

CobainOP•4mo ago

Right I was doing that but and by default TS considered it string, doing what Dimava suggested makes this union of string literals that I wanted, thanks!

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