C#•3mo ago

how to get undefinied type in a <>

here a example what i want like to do:

Type type = ...; 
SyncedVariable<typeof(type)> s = new SyncedVariable<typeof(type)>();

Type type = ...; 
SyncedVariable<typeof(type)> s = new SyncedVariable<typeof(type)>();

14 Replies

333fred•3mo ago

You cannot do that at compile time

Marvin•3mo ago

You can either do that with Reflection at runtime or change the approach a little and use code generators

KaganoOP•3mo ago

yeah i want a simular resoultuion

333fred•3mo ago

You either need to make your context generic, or use runtime reflection

KaganoOP•3mo ago

i think i must store the type in a seperate variable in the SyncedVariable

Angius•3mo ago

Just FYI, C# is not Typescript and you would benefit from not treating it as such Chances are it's an XY issue that can be solved with generics

Marvin•3mo ago

if you cant have the entire context generic, you have to at some point do something like this:

KaganoOP•3mo ago

have anyone a example?

Angius•3mo ago

We don't really know the wider context of what you want to do, so hard to give an example

Marvin•3mo ago

C#
Type type = typeof(A);
Type genericType = typeof(B<>).MakeGenericType(type);
object isntance = Activator.CreateInstance(genericType)!;

C#
Type type = typeof(A);
Type genericType = typeof(B<>).MakeGenericType(type);
object isntance = Activator.CreateInstance(genericType)!;

very ugly

Angius•3mo ago

public void Foo<T>()
{
    Blah<T> s = new Blah<T>();
}

public void Foo<T>()
{
    Blah<T> s = new Blah<T>();
}

would be ideal Or make it a generic class or w/e

Marvin•3mo ago

i approve of trying to get the entire context generic generally reflection is the last option u want to use

Angius•3mo ago

Marvin•3mo ago

if you explain more in what context you want to use it, we could maybe give you more tips