Capacitor
In this question they just took the Charge on 6uf capacitor and Net capacitence of 4 , 12 , 6
then they did 10/2 = v across 8 , but how can they take net charge to be same as on 6 uf
![No description](https://cdn.answeroverflow.com/1272848424764571699/image.png)
14 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2...
to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Is the answer 8(10uC)/6
ans is 40 uC
Hmm
I don’t get their solution the net capacitance is 6 on the arm with 4 6 12 so v=10/6 then I am getting 8*10/6
Just dropping how I did it
If someone solves it please tell me where I went wrong
![No description](https://cdn.answeroverflow.com/1272855026448076842/image.png)
this is the solution they gave i cant understand too
no Net capacitece is 2 i calculated too
Oh then I got it
Mentally kar rha tha 😭😭 should I write it down
wait u took net and on that Net Capacitence u took charge to be 10?
Yes since we know current passing through the arm is same in the whole arm toh Q on 6 must be the same charge passing through all
ohhh
Capacitance does not depend on Q or V
Remember that
ye
+solved @727
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