Capacitor

In this question they just took the Charge on 6uf capacitor and Net capacitence of 4 , 12 , 6 then they did 10/2 = v across 8 , but how can they take net charge to be same as on 6 uf
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14 Replies
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@Gyro Gearloose
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727
7276mo ago
Is the answer 8(10uC)/6
Gamertug
GamertugOP6mo ago
ans is 40 uC
727
7276mo ago
Hmm I don’t get their solution the net capacitance is 6 on the arm with 4 6 12 so v=10/6 then I am getting 8*10/6 Just dropping how I did it If someone solves it please tell me where I went wrong
Gamertug
GamertugOP6mo ago
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Gamertug
GamertugOP6mo ago
this is the solution they gave i cant understand too no Net capacitece is 2 i calculated too
727
7276mo ago
Oh then I got it Mentally kar rha tha 😭😭 should I write it down
Gamertug
GamertugOP6mo ago
wait u took net and on that Net Capacitence u took charge to be 10?
727
7276mo ago
Yes since we know current passing through the arm is same in the whole arm toh Q on 6 must be the same charge passing through all
Gamertug
GamertugOP6mo ago
ohhh
727
7276mo ago
Capacitance does not depend on Q or V Remember that
Gamertug
GamertugOP6mo ago
ye +solved @727
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