convert n-tree to dictionary based on depth

public Map<Integer, List<Integer>> toDict() {

Map<Integer, List<Integer>> dict = new HashMap<>();
Queue<Node> queue = new LinkedList<>();
queue.add(root);
int depth = 0;

while (!queue.isEmpty()) {
int levelSize = queue.size();
List<Integer> currentLevel = new ArrayList<>();

for (int i = 0; i < levelSize; i++) {
Node node = queue.poll();
currentLevel.add(node.getValue());

// Add all children of the current node to the queue
for (Node child : node.children) {
queue.add(child);
}
}
dict.put(depth, currentLevel);
depth++;
}
return dict;
}
public Map<Integer, List<Integer>> toDict() {

Map<Integer, List<Integer>> dict = new HashMap<>();
Queue<Node> queue = new LinkedList<>();
queue.add(root);
int depth = 0;

while (!queue.isEmpty()) {
int levelSize = queue.size();
List<Integer> currentLevel = new ArrayList<>();

for (int i = 0; i < levelSize; i++) {
Node node = queue.poll();
currentLevel.add(node.getValue());

// Add all children of the current node to the queue
for (Node child : node.children) {
queue.add(child);
}
}
dict.put(depth, currentLevel);
depth++;
}
return dict;
}
I wrote this function to convert a tree into a dictionary where the depth is mapped to the nodes on that depth (i.e. 0->root) is there a better way to do this?
3 Replies
JavaBot
JavaBot4mo ago
This post has been reserved for your question.
Hey @asdru! Please use /close or the Close Post button above when your problem is solved. Please remember to follow the help guidelines. This post will be automatically closed after 300 minutes of inactivity.
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szatkus
szatkus4mo ago
You can replace the loop with queue.addAll(node.children)
JavaBot
JavaBot4mo ago
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