8 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.option 4
acceleration will be g at highest point but at that instant change of speed will be 0, and then u use v²/R=g cos90 formula to find radius of curvature
There will be no acceleration at the highest point because gravity acts along Y axis and no acceleration acts along X axis, and when u draw a tangent at the highest it will be along x axis, hence acc is zero
As for radius of curvature, from circular motion wkt centripetal acc = v square / r , the centripetal acc acts inwards so here that is nothing but the acc along y axis which is g
So acc = v2/R
R = u2cos2theta/g
@v.sherylfrancia
you good?
@Irreplaceable the question asked the rate of change of "speed" not "velocity"
Rate of change of speed is tangential acceleration which is 0 the rate of change of velocity is indeed g
+solved @Priyam Alok @stormycloud @g-sus
Post locked and archived successfully!
Archived by
<@1035556259417571408> (1035556259417571408)
Time
<t:1722999985:R>
Solved by
<@582564114631491605> (582564114631491605), <@821702877721657374> (821702877721657374), <@925057461893865474> (925057461893865474)