Atomic structure

idk what i have done but did something that seemed logical to me plss correct me. thanks
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Gaurav
GauravOP9mo ago
its incorrect😭
Gaurav
GauravOP9mo ago
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ᴘɪᴄᴄʜɪ | 🎧 🎶
lmfao i recognised the teacher from the handwriting 😭
iTeachChem
iTeachChem9mo ago
oh lol it is not 3.4 but 3.3 xD hahahaha wait so theenergy is higher than what is required, what is the issue with that? why cant it absorb only 10.2 and goto 3.4? will have to think about this. what was the explanation given by the teacher?
Jiya
Jiya9mo ago
Sir a similar explanation was given by our chem teacher, he said that an atom will not get exicited if the energy is higher or lower, it must be only -3.4 ev. He said that no excitation happens and all the energy is used to translate the atom
Jiya
Jiya9mo ago
yes sir it'll be great if you could explain it to us after that since even I didnt quite understand this makes sense sir
Deleted User
Deleted User9mo ago
I think the reason is,photonic energy is quantised....we cant "cut" some part of the incident energy.
iTeachChem
iTeachChem9mo ago
sure but the amount you absorb is quantised na but again, i will have to read lol from the absorption spectra example, i thought it could work but will have to read properly wiat let us summon some pros @myst1cboomer @amethystninja any inputs on this?
amethystninja
amethystninja9mo ago
From what I understand, in such a case, it's like it absorbs and goes to an unstable orbit and then releases a very specific amount of energy in the form of a photon to go to the just lower orbit But that's when you assume it can do that I think since the initial absorption leads it to an unstable orbit, it simply re-emits all the extra energy and returns to its original state
myst1cboomer
myst1cboomer9mo ago
Nothing happens It is a rule that the energy should be exactly same as the amount req for transition
Jiya
Jiya9mo ago
but why? what explains it?
myst1cboomer
myst1cboomer9mo ago
I think it is the fact that more than required energy makes it unstable in that state and therefore because of development of some potential energy kinetic energy decreases and velocity also decreases and nh/2pie rule gets broken? The main thing always is the nh/2pie rule Aarey sir 🙏🙏
Gaurav
GauravOP9mo ago
who? extra energy will convert into KE
ᴘɪᴄᴄʜɪ | 🎧 🎶
bj most probably
Gaurav
GauravOP9mo ago
yeah
Gaurav
GauravOP9mo ago
How was your experience with him?
ᴘɪᴄᴄʜɪ | 🎧 🎶
accha padhate hai ngl
Gaurav
GauravOP9mo ago
yeah
ᴘɪᴄᴄʜɪ | 🎧 🎶
just keep on following him dpp puri krlena
Gaurav
GauravOP9mo ago
vo to milti hi nhi💀
ᴘɪᴄᴄʜɪ | 🎧 🎶
book hogi unki wtv that was
Gaurav
GauravOP9mo ago
sheet
ᴘɪᴄᴄʜɪ | 🎧 🎶
i forgor yeah class notes are pretty good for revising
Gaurav
GauravOP9mo ago
yeah his writing and notes are completely ironic but bro extra energy to KE me convert ho jati hai Sir, what he told later in some topic that the extra energy will convert up into KE so is this another exception?
iTeachChem
iTeachChem9mo ago
i dont know about this :D
Gaurav
GauravOP9mo ago
i think i should send you his explanation please delete after watching it 😉
iTeachChem
iTeachChem9mo ago
cool ty :)
myst1cboomer
myst1cboomer9mo ago
yea mb but i excess energy first gets stored as potential then gets converted correction angular momentum wala toh break hoga
Deleted User
Deleted User9mo ago
sir i meant something like this:- say in some scenario, the energy of transition from some orbit to other is 3.5 ev (hypothetical value, just saying). and we got photons (EM radiation in the sense), of say 5 ev. now thinking of it like this, photon is the most fundamental level of energy packet, so if we think like the 5 ev photon (say 1st one in number) will dissociate into two of energy 3.5ev and 1.5ev, then it is not possible. hence the incident energy must be equal to the energy gap required to jump,not less,not more. because we cant "dissociate" this incoming photon acc. to our needs.
Gaurav
GauravOP9mo ago
but excess energy gets converted to KE ig
!Nimay¡
!Nimay¡9mo ago
Electronic transitions have a narrow linewidth i.e. a range of values just above and below the frequency where transition occurs. It does exist and transition does occur if the frequency falls in that range but it is so narrow that we can neglect it for jee purpose So if you are solving any numerical and it’s not the exact value just mark transition won’t occur vala option lol
Deleted User
Deleted User9mo ago
but that is due to uncertanity in energy in a present orbital stage right? ig we would ignore that at h.s. level.
!Nimay¡
!Nimay¡9mo ago
Yeah
Gaurav
GauravOP9mo ago
this thing is hell confusing
iTeachChem
iTeachChem9mo ago
is this sorted? shall we mark this as solved?
Gaurav
GauravOP9mo ago
not sorted ig but if you want you can,Sir
iTeachChem
iTeachChem9mo ago
What do ya need? And please close your own posts :)
stormycloud
stormycloud9mo ago
But won’t that energy gap somewhat act as a per day threshold energy? Cuz we can’t write the energy in form of h x frequency , and wkt KE = h[given frequency] - h[threshold frequncy] so here we aren’t considering that the electron doesn’t get excited if it is not the exact energy right, instead we r considering it should be more than minimum fixed value right?
!Nimay¡
!Nimay¡9mo ago
Lol just keep in mind that exact value nahi ho toh no transition (there’s a linewidth as I said but negligible so ignore)
iTeachChem
iTeachChem9mo ago
this @Gaurav
Gaurav
GauravOP9mo ago
so even if thodi si bhi value upar neeche ho gyi to transition ni hoga? +solved @!Nimay¡
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