chemistry - energy or orbital
So p orbiatls are of three types that is px , py and pz right? So when they ask abt the energy comparison example:
The energy of px is :
1,Greater than s orbital
2,Equal to s orbital
3,Equal to py and pz orbital
4,Greater than d orbital
[all n value same]
What is the answer/s ?
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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Energy of orbital* typo sry
1 and 3
The answer is the px orbital will have approximately the same energy level as py and pz orbital since it is just two other ways of representing the same orbital. It definitely has more energy than the s orbital
Px, Py and Pz are degenerate, if I recall correctly so they have the same energy.
So answer is 1 and 3
The same goes for all d and f orbitals
But the energies are greater than s orbital so, 1 is also correct.
So when they ask px orbital , can I consider it the same as p orbital? Or would that be incorrect ?
Ty
Mhm tysm
I am confused abt the degenerate and the orbital thing, like is px and p the same thing ? [like is px is just the x axis it is along?]
yup you actually are on the right track, they are just characterisation of spatial orientation, otherwise are at same energy values.
Yes
Ohh okk, so like when I draw the three boxes for p , it means each of the box is a p orbital and not it as a whole [all three]?
Tyy
And each box represents p orbital along x y z bc the magnetic qn is diff for each?
Yes, that's the correct idea. The x or y or z just tells you the orientation on the three dimensional Cartesian plane.
The whole is the subshell, not the orbital, yes.
@iTeachChem , sir, if I remember correctly, didn't they prove Bohr was correct about his estimation of orbits through Schroedinger's equation?
Atomic Structure is rather interesting but I tend to lose track sometimes.
Oh ok so when I refer to the whole thing it is p subshell and when I refer to one box it is p orbital ?
righto. the energy formula worked. orbits well that is a bit of a grey area :D swill have to read up, sorta yes
Yes.
Hmm,
Bohr was a good scientist. I sort of liked his way of thinking.
same. especially the fast/slow mocing neutron paradox, and why it exicites uranium at any rate...
Ahh tysmmmm
+solved @RDES @Deleted User @Mohit @loki61
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