C#•2w ago

✅ where constraint on interface method

Is it even possible? Like public void RefuelCar<c>(c Car) where c : IUseGas.Refuel Here the generic type is constrainted to where it implements an interface's method, whereas the name of the interface is IUseGas

16 Replies

TahaA•2w ago

The name of the method is Refuel() ofc

Angius•2w ago

That doesn't make sense And doesn't work, of course Classes have to implement all methods of an interface

TahaA•2w ago

That's what I thought. I asked because I just came back from my endterm exam where they demanded that we used it like that.

Angius•2w ago

It makes no sense to check if a class implements one particular method of it It has to

MODiX•2w ago

Angius

REPL Result: Failure

interface IFoo
{
    void Bar();
}

void Baz<T>(T thing) where T : IFoo.Bar { }

interface IFoo
{
    void Bar();
}

void Baz<T>(T thing) where T : IFoo.Bar { }

Exception: CompilationErrorException

- The type name 'Bar' does not exist in the type 'IFoo'

- The type name 'Bar' does not exist in the type 'IFoo'

Compile: 233.972ms | Execution: 0.000ms | React with ❌ to remove this embed.

Angius•2w ago

It won't even compile

TahaA•2w ago

That's what I thought, too. That's why I didn't do it on the endterm, took my 1.3 points out of 2, so I missed 0.7 because of that. Seems like some teacher made the exam without either checking it himself or let another check. Too condfident in their code and not doing their job right.

Angius•2w ago

Yeah Whoever required you to do this way was high on fentanyl Unless, idk, it wasn't actually C#? Lowercase types and uppercase method params, assuming that's how it looked on the exam, are not a C# naming convention

TahaA•2w ago

Yeah I was also confused because of how c wasn't uppercase.