Drizzle Team•4mo ago

Way to get relations via typeof someSchema.$inferSelect?

Is there a way to get a type of a database schema with the relations included? Currently, I get my Account type like this:

type Account = typeof accountSchema.$inferSelect

type Account = typeof accountSchema.$inferSelect

But that doesn't give me the relations I've built into the Account type (in my case I have a profile relation similar to the profile_info example in the docs. Do I just need to build this manually? Something like this?

type Account = typeof accountSchema.$inferSelect & {
  profile: Profile
}

type Account = typeof accountSchema.$inferSelect & {
  profile: Profile
}

Drizzle ORM - Query

Drizzle ORM is a lightweight and performant TypeScript ORM with developer experience in mind.

3 Replies

Sillvva•4mo ago

You can do it that way. You can also use this custom helper type.

import * as schema from "$server/db/schema";
import {
    type BuildQueryResult,
    type DBQueryConfig,
    type ExtractTablesWithRelations
} from "drizzle-orm";

type TSchema = ExtractTablesWithRelations<typeof schema>;

export type QueryConfig<TableName extends keyof TSchema> = 
  DBQueryConfig<"one" | "many", boolean, TSchema, TSchema[TableName]>;

export type InferQueryModel<
  TableName extends keyof TSchema, 
  QBConfig extends QueryConfig<TableName> = {}
> = BuildQueryResult<
    TSchema,
    TSchema[TableName],
    QBConfig
>;

import * as schema from "$server/db/schema";
import {
    type BuildQueryResult,
    type DBQueryConfig,
    type ExtractTablesWithRelations
} from "drizzle-orm";

type TSchema = ExtractTablesWithRelations<typeof schema>;

export type QueryConfig<TableName extends keyof TSchema> = 
  DBQueryConfig<"one" | "many", boolean, TSchema, TSchema[TableName]>;

export type InferQueryModel<
  TableName extends keyof TSchema, 
  QBConfig extends QueryConfig<TableName> = {}
> = BuildQueryResult<
    TSchema,
    TSchema[TableName],
    QBConfig
>;

Then you use it like this. First parameter is base table name, second is the same query object drizzle users for relational queries.

type Result = InferQueryModel<
  "logs",
  {
    columns: { id: true },
    with: {
      character: {
        columns: { id: true }
      }
    }
  }
>;

// type Result = { id: string; character: { id: string; } }

type Result = InferQueryModel<
  "logs",
  {
    columns: { id: true },
    with: {
      character: {
        columns: { id: true }
      }
    }
  }
>;

// type Result = { id: string; character: { id: string; } }

dp•4mo ago

Awesome, thank you!

Seifeddine LARGAT•4mo ago

hey i found a more precise one on a github discussion (and i'm using it) :

import type { BuildQueryResult, DBQueryConfig, ExtractTablesWithRelations } from 'drizzle-orm';
import type { Exact } from 'type-fest';// <-- you must install type-fest
import * as schema from '../secure/db/schemas';
type TSchema = ExtractTablesWithRelations<typeof schema>;

export type QueryConfig<TableName extends keyof TSchema> = DBQueryConfig<
    'one' | 'many',
    boolean,
    TSchema,
    TSchema[TableName]
>;

export type InferQueryModel<
    TableName extends keyof TSchema,
    QBConfig extends Exact<QueryConfig<TableName>, QBConfig> = {} // <-- notice Exact here
> = BuildQueryResult<TSchema, TSchema[TableName], QBConfig>;

import type { BuildQueryResult, DBQueryConfig, ExtractTablesWithRelations } from 'drizzle-orm';
import type { Exact } from 'type-fest';// <-- you must install type-fest
import * as schema from '../secure/db/schemas';
type TSchema = ExtractTablesWithRelations<typeof schema>;

export type QueryConfig<TableName extends keyof TSchema> = DBQueryConfig<
    'one' | 'many',
    boolean,
    TSchema,
    TSchema[TableName]
>;

export type InferQueryModel<
    TableName extends keyof TSchema,
    QBConfig extends Exact<QueryConfig<TableName>, QBConfig> = {} // <-- notice Exact here
> = BuildQueryResult<TSchema, TSchema[TableName], QBConfig>;

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Way to get relations via typeof someSchema.$inferSelect?