Filament•7mo ago

Format state of select filter

I have a select filter with a relationship: SelectFilter::make('employee')->relationship('employee', 'name'). I need to modify de label of each option to show ID + name instead of the name only. formatStateUsing() is not available here.

Solution:

->getOptionLabelFromRecordUsing(fn (Employee $record) => "{$record->id} {$record->name}")

->getOptionLabelFromRecordUsing(fn (Employee $record) => "{$record->id} {$record->name}")

...

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4 Replies

prowler•7mo ago

SelectFilter::make('employee')
    ->relationship('employee', 'name')
    ->preload()
    ->options(function () {
        return Employee::all()->pluck('name', 'id')->mapWithKeys(function ($name, $id) {
            return [$id => $id . ' - ' . $name];
        });
    })

SelectFilter::make('employee')
    ->relationship('employee', 'name')
    ->preload()
    ->options(function () {
        return Employee::all()->pluck('name', 'id')->mapWithKeys(function ($name, $id) {
            return [$id => $id . ' - ' . $name];
        });
    })

Solution

LeandroFerreira•7mo ago

->getOptionLabelFromRecordUsing(fn (Employee $record) => "{$record->id} {$record->name}")

->getOptionLabelFromRecordUsing(fn (Employee $record) => "{$record->id} {$record->name}")

RomeOP•7mo ago

Not working when you have a relationship() method, but thanks! Working! Thanks a lot! Didn't find in the doc, I was searching on "Table Builder" -> "Filters".

LeandroFerreira•7mo ago

No problem, this is here https://filamentphp.com/docs/3.x/forms/fields/select#customizing-the-relationship-option-labels

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Format state of select filter