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@Dexter
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.attempt please 🙂 what are the underlying reactions?
those are my module questions 😠i cant understand anything 💀
i didnt understand the part "preparing 12% cd-hg on a cathode of 2g hg"
what equation do i form from that
ohhhhhhh theek haiii
do you have the link?
ðŸ«
mass/mass %
mass of solute by total mass of solution x 100 g
so 12 = x/(x + 2) x 100 (since the deposition happens on the electrode, increasing its mass)
what if we consider it like:
12 g of cd and 88g of hg or 88g of cd and 12 g of hg
na it is 12 g of Hg-Cd (thta is an amalgum)
in 100 g of solution
but
it is given that the solvent is 2g
so you take this x thingy
nahhh like i dont wanna take the x
if it was 12g of cd in 88g hg then we take it for 2g of hg and vice versa
would it be 12g cd or 12g hg
sure, means the same thing
and you are depositing Cd right so 12% refers to Cd
also, it should be CdCl2 in the q right Ca doesnt fit
yaha Cd ka source kya hai tho (dumb question? idk electro padhi nahi bohot time se 🤡)
ohhhhh okay okay
wym
kis cheez ki dissociation se Cd metal produce ho rha?
CaCl2 toh calcium dega na
cdcl2 hai wahan pe q galat hai
accha
yeah yeah it is cdcl2
+solved @iTeachChem
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