C#•3mo ago

✅ how can i let an interface implement a function of a super-interface, instead of shadowing it?

public class MyClass : IOne;

public interface IOne : ITwo
{
    public void Foo()
    {
        Console.WriteLine();
    }
}

public interface ITwo
{
    public void Foo();
}

public class MyClass : IOne;

public interface IOne : ITwo
{
    public void Foo()
    {
        Console.WriteLine();
    }
}

public interface ITwo
{
    public void Foo();
}

this doesnt compile, because IOne.Foo is considered a separate function that shadows ITwo.Foo. how do i tell IOne to provide a default implementation for ITwo.Foo instead of shadowing it?

8 Replies

Unknown User•3mo ago

Message Not Public

MODiX•3mo ago

TeBeCo

REPL Result: Success

using System;

var foo = new MyClass();

foo.Foo();
((IOne)foo).Foo();
((ITwo)foo).Foo();

public interface IOne : ITwo {}

public interface ITwo
{
    void Foo(); // no scope on interface member ... because it's the interface
}

public class MyClass : IOne
{
     public void Foo()
     {
        Console.WriteLine("1");
     }

    void ITwo.Foo()
    {
        Console.WriteLine("2");
    }
}

using System;

var foo = new MyClass();

foo.Foo();
((IOne)foo).Foo();
((ITwo)foo).Foo();

public interface IOne : ITwo {}

public interface ITwo
{
    void Foo(); // no scope on interface member ... because it's the interface
}

public class MyClass : IOne
{
     public void Foo()
     {
        Console.WriteLine("1");
     }

    void ITwo.Foo()
    {
        Console.WriteLine("2");
    }
}

Console Output

1
2
2

1
2
2

Compile: 504.000ms | Execution: 28.647ms | React with ❌ to remove this embed.

LastExceed•3mo ago

this is exactly what i was looking for, thanks!

Unknown User•3mo ago

Message Not Public

LastExceed•3mo ago

i dont know what it means either xD

Unknown User•3mo ago

Message Not Public

MODiX•3mo ago

TeBeCo

REPL Result: Success

using System;

var foo = new MyClass();

((IOne)foo).Foo();
((ITwo)foo).Foo();

foo.Foo();

public interface IOne
{
    void Foo(); // no scope on interface member ... because it's the interface
}

public interface ITwo
{
    void Foo(); // no scope on interface member ... because it's the interface
}

public class MyClass : IOne, ITwo
{
    void IOne.Foo() => Console.WriteLine("1");

    void ITwo.Foo() => Console.WriteLine("2");
    
    public void Foo() => Console.WriteLine("other");
}

using System;

var foo = new MyClass();

((IOne)foo).Foo();
((ITwo)foo).Foo();

foo.Foo();

public interface IOne
{
    void Foo(); // no scope on interface member ... because it's the interface
}

public interface ITwo
{
    void Foo(); // no scope on interface member ... because it's the interface
}

public class MyClass : IOne, ITwo
{
    void IOne.Foo() => Console.WriteLine("1");

    void ITwo.Foo() => Console.WriteLine("2");
    
    public void Foo() => Console.WriteLine("other");
}

Console Output

1
2
other

1
2
other

Compile: 508.964ms | Execution: 29.475ms | React with ❌ to remove this embed.

LastExceed•3mo ago

well its an isolated example. my use case isn't that simple of course

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✅ how can i let an interface implement a function of a super-interface, instead of shadowing it?