C#•8mo ago

Basic calculator application

Hello I just made this application but im not sure if there is a better or more optimized way to make this kind of program. If anyone would be interesting in helping it would be much appreciated!

11 Replies

Denis•8mo ago

There is no need to do a convert to string on the Console.Readline It returns a string right away

Jimmacle•8mo ago

what happens if i type "potato" instead of a number? also, instead of saying "error try again" if they don't choose a valid operator, tell them they chose an invalid operator

Denis•8mo ago

Also Convert.To.... isn't the model way of parsing strings to other types

Jimmacle•8mo ago

$tryparse

MODiX•8mo ago

When you don't know if a string is actually a number when handling user input, use int.TryParse (or variants, e.g. double.TryParse)

if(int.TryParse("123", out int number))
{
    var total = number + 1;
    Console.WriteLine(total); // output: 124
}

if(int.TryParse("123", out int number))
{
    var total = number + 1;
    Console.WriteLine(total); // output: 124
}

TryParse returns a bool, where true indicates successful parsing. Remarks: - Avoid int.Parse if you do not know if the value parsed is definitely a number. - Avoid Convert.ToInt32 entirely, this is an older method and Parse should be preferred where you know the string can be parsed. Read more here

Denis•8mo ago

Use, e.g., dynamic.TryParse(...)

Jimmacle•8mo ago

(i think you mean decimal)

Denis•8mo ago

Ah yes Sorry

CodeGeekOP•8mo ago

Thank you guys for all your feedback Ill make sure to make those changes!

Angius•8mo ago

Protip when it comes to dynamic: use the banned APIs analyzer to blanket-ban it from every project you start

Servator•8mo ago

Also don't forget DRY (Don't Repeat Yourself) principle Instead of using Console.WriteLine() for each operation Just output at the end of code

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Basic calculator application