10 Replies
@Dexter
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.udhar negative aa jayega
sahi toh hai
deprotonation ke baad
carbanion banega upar
side ke jo 2 double bond h dusre ring me
that is shared between
middle one too
toh uss double bond ko bhi middle me consider karenge
toh carbanion ka 2 pi electron
plus side ke double bonds ka 4
toh 6 = 4*1 + 2 electrons
therefore
aromatic
@Nikey
to fir 6 electrons aa jayenge, resonance me 4 from alkele, 2 from negative charges, aur planar to hai hi
@.sidd. ðŸ˜mera timer chal rha tha tb tk me tumne 20 messages kr diye
sorry to be that person but I don't speak Hindi
@Weirdo
Na it’s absolutely fine fam.
ohh so anion and the two double bonds will be in conjugation
right okay thank youu
+solved @.sidd.
+solved @Law of Reversibility
+solved @Law of Reversibility
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