Filament•8mo ago

deep relationship

I have 3 models User, Car, and Brand and the relationship is User > Car > Brand I created a UserResource and I want to fetch the brand name

Tables\Columns\TextColumn::make('car')
                    ->formatStateUsing(fn(Car $car): string => $car->brand->name)
                    ->sortable(),

Tables\Columns\TextColumn::make('car')
                    ->formatStateUsing(fn(Car $car): string => $car->brand->name)
                    ->sortable(),

with the code above i get "Attempt to read property "name" on null"

Solution:

solved it ```php Tables\Columns\TextColumn::make('car_id') ->formatStateUsing(...

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2 Replies

Solution

Lucky0•8mo ago

solved it

Tables\Columns\TextColumn::make('car_id')
                    ->formatStateUsing(
                        function ($state, Car $car): string {
                            $query = $car->with('brand')->where('id', $state)->first();
                            return $query->brand->name . ' - ' . $query->name->name;
                        }
                    )
                    ->sortable(),

Tables\Columns\TextColumn::make('car_id')
                    ->formatStateUsing(
                        function ($state, Car $car): string {
                            $query = $car->with('brand')->where('id', $state)->first();
                            return $query->brand->name . ' - ' . $query->name->name;
                        }
                    )
                    ->sortable(),

Lucky0OP•8mo ago

I'm wondering if there are any better solution than this.

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deep relationship