C
C#8mo ago
zzz

reading files from a directory

using System.IO;

namespace Program
{
class program
{
public static void FileLoader()
{
string[] filePaths = Directory.GetFiles(@"C:\Users\joesm\Source\Repos\441101-2324-digital-portfolio-jsd6666\Summative 4\", "*.mark", SearchOption.TopDirectoryOnly);
for (int i = 0; i < filePaths.Length; i++)
{
Console.WriteLine($"{i + 1}. {filePaths[i]}");
}
int fileSelect = int.Parse(Console.ReadLine());
}
public static void Main()
{
Console.WriteLine("Please select a file to load.");
FileLoader();
}
}
}
using System.IO;

namespace Program
{
class program
{
public static void FileLoader()
{
string[] filePaths = Directory.GetFiles(@"C:\Users\joesm\Source\Repos\441101-2324-digital-portfolio-jsd6666\Summative 4\", "*.mark", SearchOption.TopDirectoryOnly);
for (int i = 0; i < filePaths.Length; i++)
{
Console.WriteLine($"{i + 1}. {filePaths[i]}");
}
int fileSelect = int.Parse(Console.ReadLine());
}
public static void Main()
{
Console.WriteLine("Please select a file to load.");
FileLoader();
}
}
}
its showing me the file names with the directory included, i just want it to display the file name on each line without the directory??
No description
12 Replies
Angius
Angius8mo ago
Split the path by \ and get just the last segment That'll be the easiest way
MODiX
MODiX8mo ago
Angius
REPL Result: Success
var path = @"C:\Foo\Bar\Baz\My Cool Files\File.png";
var segments = path.Split('\\');
segments[^1]
var path = @"C:\Foo\Bar\Baz\My Cool Files\File.png";
var segments = path.Split('\\');
segments[^1]
Result: string
File.png
File.png
Compile: 387.446ms | Execution: 31.870ms | React with ❌ to remove this embed.
Jimmacle
Jimmacle8mo ago
no need to implement the splitting yourself
mtreit
mtreit8mo ago
Use DirectoryInfo and FileInfo types instead for this kind of thing.
var directory = new DirectoryInfo(@"c:\temp");
var files = directory.GetFiles();
foreach (var file in files)
{
Console.WriteLine(file.Name);
}
var directory = new DirectoryInfo(@"c:\temp");
var files = directory.GetFiles();
foreach (var file in files)
{
Console.WriteLine(file.Name);
}
zzz
zzzOP8mo ago
i understand the use for 1 file but i dont understand how i can use iterations to get all file name s in a directory
Angius
Angius8mo ago
You get all the file paths and, in a loop, extract the file names from them
mtreit
mtreit8mo ago
The code I showed does exactly that.
zzz
zzzOP8mo ago
can you show me bro i dont want to just copy paste this code i dont understand ive just been staring at this shit for an hour trying not to punch a wall
Jimmacle
Jimmacle8mo ago
so you already have a loop with the absolute path to the file in filePaths[i] pick either Path.GetFileName or manually splitting and use that to get just the name or rewrite the whole thing based on mtreit's example
zzz
zzzOP8mo ago
public static void FileSelecter()
{
string rootPath = @"C:\Users\joesm\Source\Repos\441101-2324-digital-portfolio-jsd6666\Summative 4";
var files = Directory.GetFiles(rootPath, "*.mark", SearchOption.TopDirectoryOnly);
int count = 1;
foreach (string file in files)
{
Console.WriteLine($"{count}. {Path.GetFileName(file)}");
count = count + 1;
}
int fileSelect = int.Parse(Console.ReadLine());
FileLoader();
}
public static void FileSelecter()
{
string rootPath = @"C:\Users\joesm\Source\Repos\441101-2324-digital-portfolio-jsd6666\Summative 4";
var files = Directory.GetFiles(rootPath, "*.mark", SearchOption.TopDirectoryOnly);
int count = 1;
foreach (string file in files)
{
Console.WriteLine($"{count}. {Path.GetFileName(file)}");
count = count + 1;
}
int fileSelect = int.Parse(Console.ReadLine());
FileLoader();
}
so i got it to work but it doesnt work like before as i have no array of file names which is what i need to access the file selected
Angius
Angius8mo ago
files is the array that stores full file paths If you want to have a collection of just the file names, you can also use the loop for that Create a new List<string> that would store the names alone And, in the loop, for each path you have, add just the filename to that list Alternatively, you can use LINQ method .Select()
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