Topics

C#•9mo ago

Using MouseClick Event

https://paste.mod.gg/zlxoaubtbcom/0 Hey guys, I'm working on a code assignment where I have to use Arrays to Reverse, Swap, Clear, Delete or Insert Array Elements, with each element being a colour read in from a file. My teacher has left some parts of comments to help me organize it but I am confused on the MouseClick event - I haven't ever worked with this event before but he gave instructions on it. Any ideas on how to implement it

BlazeBin - zlxoaubtbcom

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67 Replies

Denis•9mo ago

The mouse click event provides two parameters. One of them is sender. Debug you code and see what type is hiding inside it

ArrayOP•9mo ago

For reference, here it was happens when I read in the file

No description

Denis•9mo ago

Then you could cast it to whatever is representing the color, I'd assume and select it

ArrayOP•9mo ago

 private void Form1_MouseClick(object sender, MouseEventArgs e)
        {
            //todo
            //mouse click detects if an array element selected
            //set the element selected in Selected array to true
            
        



            //call this.Refresh() if an element is selected
            this.Refresh();
        }

 private void Form1_MouseClick(object sender, MouseEventArgs e)
        {
            //todo
            //mouse click detects if an array element selected
            //set the element selected in Selected array to true
            
        



            //call this.Refresh() if an element is selected
            this.Refresh();
        }

Hey! Thanks for the reply Question - What do you mean by two parameters? "One of them is sender" What do you mean by this? Sorry if these are bad questions I am a big beginner @ZZZZZZZZZZZZZZZZZZZZZZZZZ Any chance you can help me out since you saw me code the reading it part? might make more sense to you

Angius•9mo ago

My knowledge of Winforms is minimal

ArrayOP•9mo ago

oop no worries

i like chatgpt•9mo ago

MouseEventArgs has Location property that provides the coordinates of the mouse pointer relative to the control that raised the event.

ArrayOP•9mo ago

may be relevant?

No description

i like chatgpt•9mo ago

What is the contents of the file you must load?

ArrayOP•9mo ago

It's a list, that when I load in, I get the elements (colors) of the array elements

ArrayOP•9mo ago

No description

ArrayOP•9mo ago

No description

ArrayOP•9mo ago

When I load it in, I get this

No description

ArrayOP•9mo ago

@always use bool? as primary keys I have this image referencing coordinates, but I’m not sure if this is the same?

No description

i like chatgpt•9mo ago

The first line respresents the number of squares.

ArrayOP•9mo ago

Right If you look to the right of the picture My teacher wrote some psuedo code But I’m not exactly sure if it’s for the mouse click event It could be

i like chatgpt•9mo ago

Yes. The e.X and e.Y are the MouseEventArgs e.

ArrayOP•9mo ago

So I should probably try to follow this code for the event @always use bool? as primary keys Ohhh okay yea that makes sense

i like chatgpt•9mo ago

When will this assignment be due?

ArrayOP•9mo ago

Will try to make sense of it by asking questions , by setting e.x - 50 and y - 100, what does this mean? He told us try to get it done for tomorrow but if you can't (everyone is still working on it) we can have an extra day Or if you can explain that I would appreciate that ! this part

i like chatgpt•9mo ago

DrawColourArray(e.Graphics, 50, 100); The tiles start from (50,100).

ArrayOP•9mo ago

Oh okay, like the diemsions they're drawn from? We actually did a lab similar to this so I'll check it out again for the drawing part

i like chatgpt•9mo ago

No description

ArrayOP•9mo ago

Did you draw this? Or make this

i like chatgpt•9mo ago

I made this with mspaint.exe, my favourite application.

ArrayOP•9mo ago

Omg lol Thank you for even taking the time to do that How did you get 550 and 150?

i like chatgpt•9mo ago

550 = 50 + 50 x 10 150 = 100 + 50

ArrayOP•9mo ago

Yea but why do we add 50 + 50 * 10 I see 10 comes from 10 tiles Right

i like chatgpt•9mo ago

The note on the whiteboard says that - define two variables x and y where var x = e.X - 50; and var y = e.Y - 100;. - y represents the distance of the mouse point from the top edge of tiles. - x represents the distance of the mouse point from the left edge of the most left tile. - The mouse point is on any tiles if and only if 0 <= y <= 50 and 0 <= x < 500. - To find the index of a certain tile, we can use var index = e.X / 50; For example, if x = 40 then index = 40 / 50 = 0 (truncated). The if condition can be written as what the teacher wrote or what I said above. Both are correct.

// mine
if(y>=0 && y<=50 && x>=0 && x<500)
{
    // ...
}

// mine
if(y>=0 && y<=50 && x>=0 && x<500)
{
    // ...
}

// your teacher
if(y>=0 && y<=50 && x>=0 && x/50<10)
{
    // ...
}

// your teacher
if(y>=0 && y<=50 && x>=0 && x/50<10)
{
    // ...
}

I think mine is negligibly faster. Yes.

ArrayOP•9mo ago

Sorry My dad was talking to me, back reading this

i like chatgpt•9mo ago

Does your dad know programming?

ArrayOP•9mo ago

When you say distance from mouse point, wdym? Oh nah he was talking to me about something completely unrelated Sorry lol 😅

i like chatgpt•9mo ago

Distance between a point and a line is defined as the shortest distance from the point to the line. 🙂 Distance between a mouse point to the top edge of a tile means the shortest distance from the mouse pointer to the top edge of the tile.

ArrayOP•9mo ago

Ok I think what’s confusing me is that I’m not exactly sure what is meant by distance - like how is distance relevant here? Like why do we give it coordinates?

i like chatgpt•9mo ago

Distance is the easiest way to understand why the teacher wrote

var x = e.X - 50;
var y = e.Y - 100;

var x = e.X - 50;
var y = e.Y - 100;

x and y are about distance in disguise.

ArrayOP•9mo ago

Gotcha

i like chatgpt•9mo ago

No description

ArrayOP•9mo ago

What’s that? 😅

i like chatgpt•9mo ago

finding distance with broken rulers.

ArrayOP•9mo ago

Lol So does the coordinates of 50,100 say like you can click from 50 on the and 100 on the y? Like it’s the distance/area where you can click?

i like chatgpt•9mo ago

Yes. you can click tiles if the mouse position (e.X,e.Y) in the region from (50,100) to (550,150). or the distance (x,y) in the region/interval (0,0) to (500,50)

ArrayOP•9mo ago

Oh okay I gotchu Yea that makes sense, the squares are 50 long I like your method

i like chatgpt•9mo ago

Introducing x and y is not mandatory actually. But I just follow what the teacher wrote.

ArrayOP•9mo ago

For the if statement, if the mouse e.X is greater than 50 and less than 550 and e.Y is less than 150 and greater than 100, then we set index to be o be true Also I realize my teacher has x/50 < Colors.Length, does that have any relevance?

i like chatgpt•9mo ago

x/50 represents the index and the index starts from 0 to 9. That is why x/50 must be less than 10 which is the length of the Colors array.

ArrayOP•9mo ago

Just curious, why is the index = e.X / 50 ? I get the general idea thought it makes sense why it is less than the length of colors array Like you can only go from 0 to 9 (becuse element = 0 is your first element) I'm wondering why it is divided by 50 tho, oes it just represent one X tile maybe?

i like chatgpt•9mo ago

- 0 <= x < 50 represents tile of index = 0 . Any x in this interval when divided by 50 produces 0.*** or truncated to 0. - 50 <= x < 100 represents tile of index = 1. Any x in this interval when divided by 50 produces 1.*** or truncated to 1. - ... - 450 <= x < 500 represents tile of index = 9. Any x in this interval when divided by 50 produces 9.*** or truncated to 9. So var index = x / 50; Either one is ok.

if (e.X >= 50 && e.X < 550 && e.Y >= 100 && e.Y <= 150)
{
    var index = e.X / 50 - 1;
    Selected[index] = !Selected[index];
}

if (e.X >= 50 && e.X < 550 && e.Y >= 100 && e.Y <= 150)
{
    var index = e.X / 50 - 1;
    Selected[index] = !Selected[index];
}

or

var x = e.X - 50;
var y = e.Y - 100;
if (x >= 0 && x / 50 < 10 && y >= 0 && y <= 50)
{
    var index = x / 50;
    Selected[index] = !Selected[index];
}

var x = e.X - 50;
var y = e.Y - 100;
if (x >= 0 && x / 50 < 10 && y >= 0 && y <= 50)
{
    var index = x / 50;
    Selected[index] = !Selected[index];
}

or

var x = e.X - 50;
var y = e.Y - 100;
if (x >= 0 && x < 500 && y >= 0 && y <= 50)
{
    var index = x / 50;
    Selected[index] = !Selected[index];
}

var x = e.X - 50;
var y = e.Y - 100;
if (x >= 0 && x < 500 && y >= 0 && y <= 50)
{
    var index = x / 50;
    Selected[index] = !Selected[index];
}

ArrayOP•9mo ago

Gotcha! Can I ask, I realize when you don’t define x and y you have it set to the 150/550 bounds

i like chatgpt•9mo ago

yes

ArrayOP•9mo ago

Why not?

i like chatgpt•9mo ago

because I use e.X and e.Y as the distance from the mouse pointer to the left edge and top edge of the window repectively. Just another note: The following is wrong

var x = e.X - 50;
var y = e.Y - 100;
var index = x / 50;
if (index >= 0 && index < 10 && y >= 0 && y <= 50)
{
    Selected[index] = !Selected[index];
}

var x = e.X - 50;
var y = e.Y - 100;
var index = x / 50;
if (index >= 0 && index < 10 && y >= 0 && y <= 50)
{
    Selected[index] = !Selected[index];
}

but the following is correct

var x = e.X - 50;
var y = e.Y - 100;
var index = x / 50;
if (e.X > 0 && index < 10 && y >= 0 && y <= 50)
{
    Selected[index] = !Selected[index];
}

var x = e.X - 50;
var y = e.Y - 100;
var index = x / 50;
if (e.X > 0 && index < 10 && y >= 0 && y <= 50)
{
    Selected[index] = !Selected[index];
}

ArrayOP•9mo ago

I see Thank you so much man I am eating dinner but I really appreciate you taking time to help me out Words can’t describe the feeling when you’re stuck on something n someone clears it up I want to add some header comments to explain what I did, any suggestions for the if statement?

i like chatgpt•9mo ago

Wait in 8 hours. I am preparing to sleep sound now. 🙂 https://tenor.com/view/procrastiner-lsf-usm67-sign-language-gif-15604190

Tenor

ArrayOP•9mo ago

Good night!

ArrayOP•9mo ago

(for reference), I can only press on all but one

No description

i like chatgpt•9mo ago

What is your code?

ArrayOP•9mo ago

private void Form1_MouseClick(object sender, MouseEventArgs e)
{
    //todo
    //mouse click detects if an array element selected
    //set the element selected in Selected array to true

    int X = e.X - 50;
    int Y = e.Y - 100;
    int Index = X / 50;
    if (Index > 0 && Index < 10 && Y >= 0 && Y <= 50)
    {
        Selected[Index] = !Selected[Index];

    }

private void Form1_MouseClick(object sender, MouseEventArgs e)
{
    //todo
    //mouse click detects if an array element selected
    //set the element selected in Selected array to true

    int X = e.X - 50;
    int Y = e.Y - 100;
    int Index = X / 50;
    if (Index > 0 && Index < 10 && Y >= 0 && Y <= 50)
    {
        Selected[Index] = !Selected[Index];

    }

i like chatgpt•9mo ago

I see.

private void Form1_MouseClick(object sender, MouseEventArgs e)
{
    //todo
    //mouse click detects if an array element selected
    //set the element selected in Selected array to true

    int X = e.X - 50;
    int Y = e.Y - 100;
    int Index = X / 50;
    if (e.X > 0 && Index < 10 && Y >= 0 && Y <= 50)
    {        
        Selected[Index] = !Selected[Index];
    }
}

private void Form1_MouseClick(object sender, MouseEventArgs e)
{
    //todo
    //mouse click detects if an array element selected
    //set the element selected in Selected array to true

    int X = e.X - 50;
    int Y = e.Y - 100;
    int Index = X / 50;
    if (e.X > 0 && Index < 10 && Y >= 0 && Y <= 50)
    {        
        Selected[Index] = !Selected[Index];
    }
}

ArrayOP•9mo ago

I noticed earlier my teacher used Colors.Length in the if statement, maybe I could use that instead of 10?

i like chatgpt•9mo ago

Yes. Using Colors.Length is recommended because hardcoding 10 is not flexible.

ArrayOP•9mo ago

Using e.X seemed to fix it!

i like chatgpt•9mo ago

private void Form1_MouseClick(object sender, MouseEventArgs e)
{
    //todo
    //mouse click detects if an array element selected
    //set the element selected in Selected array to true

    int X = e.X - 50;
    int Y = e.Y - 100;
    int Index = X / 50;
    if (e.X > 0 && e.X < Colors.Length * 50 && Y >= 0 && Y <= 50)
    {        
        Selected[Index] = !Selected[Index];
    }
}

private void Form1_MouseClick(object sender, MouseEventArgs e)
{
    //todo
    //mouse click detects if an array element selected
    //set the element selected in Selected array to true

    int X = e.X - 50;
    int Y = e.Y - 100;
    int Index = X / 50;
    if (e.X > 0 && e.X < Colors.Length * 50 && Y >= 0 && Y <= 50)
    {        
        Selected[Index] = !Selected[Index];
    }
}

ArrayOP•9mo ago

This code makes the last element not work though I think this one with colors.length worked the best

i like chatgpt•9mo ago

Oh my ghost. I mistyped.

private void Form1_MouseClick(object sender, MouseEventArgs e)
{
    //todo
    //mouse click detects if an array element selected
    //set the element selected in Selected array to true

    int X = e.X - 50;
    int Y = e.Y - 100;
    int Index = X / SquareSize;
    if (X > 0 && X < Colors.Length * SquareSize && Y >= 0 && Y <= SquareSize)
    {        
        Selected[Index] = !Selected[Index];
    }
}

private void Form1_MouseClick(object sender, MouseEventArgs e)
{
    //todo
    //mouse click detects if an array element selected
    //set the element selected in Selected array to true

    int X = e.X - 50;
    int Y = e.Y - 100;
    int Index = X / SquareSize;
    if (X > 0 && X < Colors.Length * SquareSize && Y >= 0 && Y <= SquareSize)
    {        
        Selected[Index] = !Selected[Index];
    }
}

ArrayOP•9mo ago

This one works too! Assuming *50 represents the length of width of each element is 50 pixels right?

i like chatgpt•9mo ago

See my last edit in the previous code.

ArrayOP•9mo ago

SquareSize is new! That;s actually a smart idea cause it's a global variable within my code Also this is just a question but why did my teacher make it =! (Not true) if he wants the selected array to be true lol

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