Difference between query modes

Heyo everyone ! 👋 Is there anyway I can get same result than result1 query using result2 syntax with db.select() ?

const result1 = await db.query.notifications.findMany({
  where: eq(notifications.guild_id, interaction.guildId),
  with: {
    group: true,
  },
});

const result2 = await db
  .select()
  .from(notifications)
  .limit(1)
  .where(eq(notifications.guild_id, interaction.guildId))
  .innerJoin(groups, eq(notifications.group_id, groups._id))
  .execute();

const result1 = await db.query.notifications.findMany({
  where: eq(notifications.guild_id, interaction.guildId),
  with: {
    group: true,
  },
});

const result2 = await db
  .select()
  .from(notifications)
  .limit(1)
  .where(eq(notifications.guild_id, interaction.guildId))
  .innerJoin(groups, eq(notifications.group_id, groups._id))
  .execute();

Or should I keep using db.query if I want to retrieve notifications with group inside of it ?

1 Reply

Angelelz•12mo ago

You could do it, but you'll need to use json array aggregation sql functions You can take a look at the query that result1 produces to see what functions are used fair warning, it will be complicated if you're not familiar with sql

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Difference between query modes