C#•13mo ago

✅ @ in the property name c#

Team , Is there any way to get @ in the property name like this public class TestClass { [JsonProperty("@context)] public string @context { get; set; } } Adding Jsonproperty , I am able to deserialize . but I need @context as output property,right now it is coming as just context But Underscore is working public class TestClass { [JsonProperty("@context)] public string _context { get; set; } } Please guide on this

24 Replies

Angius•13mo ago

Why would you want the property to be called that, and not Context? [JsonProperty] handles the serialization and deserialization The name in code can just as well be UngaBunga

ShivOP•13mo ago

I need to send the same object back to an library which is expecting an @

Angius•13mo ago

It's not a valid identifier, so no library can use it either Not to mention, unless using reflections, the names of properties don't matter

Unknown User•13mo ago

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Angius•13mo ago

Json has a property named @context from what I gather

Unknown User•13mo ago

Message Not Public

Angius•13mo ago

Probably Idk, detail is scarce lol

ShivOP•13mo ago

So it is conflicting?

Unknown User•13mo ago

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Angius•13mo ago

What is conflicting with what? Handling a Json property named @context is easy with [JsonProperty] attribute The property itself cannot begin witn @ No library will ever expect a property starting with @ Why do you need specifically the property of your class to be named @Context and not Context or UngaBunga?

ShivOP•13mo ago

It is an json LD object , if i send without @ it is throwing an error saying invalid object https://json-ld.org/

Angius•13mo ago

[JsonProperty] handles the conversion to Json

MODiX•13mo ago

Angius

REPL Result: Success

using System.Text.Json;

public class Foo
{
  [JsonProperty("@context")]
  public string UngaBunga { get; set; }
}

var foo = new Foo { UngaBunga = "hello world" };

var json = JsonSerializer.Serialize(foo);

Console.WriteLine(json);

var newFoo = JsonSerializer.Deserialize<Foo>(json);

return newFoo;

using System.Text.Json;

public class Foo
{
  [JsonProperty("@context")]
  public string UngaBunga { get; set; }
}

var foo = new Foo { UngaBunga = "hello world" };

var json = JsonSerializer.Serialize(foo);

Console.WriteLine(json);

var newFoo = JsonSerializer.Deserialize<Foo>(json);

return newFoo;

Result: Foo

{
  "ungaBunga": "hello world"
}

{
  "ungaBunga": "hello world"
}

Console Output

{"UngaBunga":"hello world"}

{"UngaBunga":"hello world"}

Compile: 660.550ms | Execution: 56.581ms | React with ❌ to remove this embed.

Angius•13mo ago

Huh, what? [JsonProperty] doesn't work for serialization?

Unknown User•13mo ago

Message Not Public

Angius•13mo ago

Ah Well that's the issue lmao

Unknown User•13mo ago

Message Not Public

MODiX•13mo ago

Angius

REPL Result: Success

using System.Text.Json;
using System.Text.Json.Serialization;

public class Foo
{
  [JsonPropertyName("@context")]
  public string UngaBunga { get; set; }
}

var foo = new Foo { UngaBunga = "hello world" };

var json = JsonSerializer.Serialize(foo);

Console.WriteLine(json);

var newFoo = JsonSerializer.Deserialize<Foo>(json);

return newFoo;

using System.Text.Json;
using System.Text.Json.Serialization;

public class Foo
{
  [JsonPropertyName("@context")]
  public string UngaBunga { get; set; }
}

var foo = new Foo { UngaBunga = "hello world" };

var json = JsonSerializer.Serialize(foo);

Console.WriteLine(json);

var newFoo = JsonSerializer.Deserialize<Foo>(json);

return newFoo;

Result: Foo

{
  "@context": "hello world"
}

{
  "@context": "hello world"
}

Console Output

{"@context":"hello world"}

{"@context":"hello world"}

Compile: 657.888ms | Execution: 96.639ms | React with ❌ to remove this embed.

Angius•13mo ago

There

ShivOP•13mo ago

Should I use System.Text.Json; and not Newtonsoft.Json; ? @TeBeCo

Unknown User•13mo ago

Message Not Public

Angius•13mo ago

STJ is easier, better, faster, stronger

Angius•13mo ago

https://tenor.com/view/daftpunk-harder-better-faster-stronger-gif-11845009

Tenor

ShivOP•13mo ago

Got it. Thanks for the input @ZZZZZZZZZZZZZZZZZZZZZZZZZ @TeBeCo

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✅ @ in the property name c#