Filament•13mo ago

How do I create a custom Table Action

Hi guys, I have a resource let's title it StorefrontResource. I created a custom page based on this resource called ManageWorkers. It allows me to add members to the store. I registered the page in getPages() of the warehouse resource:

php 'manage' => Pages\ManageWorkers::route('/{record}/manage')

php 'manage' => Pages\ManageWorkers::route('/{record}/manage')

On the default list view of the StorefrontResource, how can I attach an action titled 'Manage' on the table so that when clicking it - it'll bring me to the manage workers page of the Storefront record? Storefront Resource -->Actions/ManageAction.php -->Pages/...ManageWorkers.php --StorefrontResource.php I don't want to add code in the redirect within the resource file, but rather I'd like to have a seperate action file. Is there an artisan command for creating a table action? What is the proper convention to reference the route? I'm unsure what to override in the Manage Action class. Any pointers?

<?php

namespace App\Filament\Admin\Resources\StorefrontResource\Actions;

use App\Filament\Admin\Resources\StorefrontResource;
use Closure;
use Filament\Actions\Concerns\CanCustomizeProcess;
use Filament\Tables\Actions\Action;
use Filament\Tables\Table;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\Relations\BelongsToMany;
use Illuminate\Support\Arr;

class ManageAction extends Action
{
    public static function getDefaultName(): ?string
    {
        return 'manage';
    }
}

<?php

namespace App\Filament\Admin\Resources\StorefrontResource\Actions;

use App\Filament\Admin\Resources\StorefrontResource;
use Closure;
use Filament\Actions\Concerns\CanCustomizeProcess;
use Filament\Tables\Actions\Action;
use Filament\Tables\Table;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\Relations\BelongsToMany;
use Illuminate\Support\Arr;

class ManageAction extends Action
{
    public static function getDefaultName(): ?string
    {
        return 'manage';
    }
}

Solution:

I got it working by doing this - sure it works but is this the correct way? ```php public static function make($name = 'manage'): static {...

Jump to solution

1 Reply

Solution

ashattack•13mo ago

I got it working by doing this - sure it works but is this the correct way?

    public static function make($name = 'manage'): static
    {
        return parent::make($name)
            ->url(fn ($record): string => url("/admin/storefront/{$record->getKey()}/manage"))
            ->label('Manage Workers');
    }

    public static function make($name = 'manage'): static
    {
        return parent::make($name)
            ->url(fn ($record): string => url("/admin/storefront/{$record->getKey()}/manage"))
            ->label('Manage Workers');
    }

Update: Minor refactor or route:

    public static function make($name = 'manage'): static
    {
        return parent::make($name)
            ->url(fn ($record): string => StorefrontResource::getUrl('manage', ['record' => $record->getKey()]))
            ->label('Manage Workers');
    }

    public static function make($name = 'manage'): static
    {
        return parent::make($name)
            ->url(fn ($record): string => StorefrontResource::getUrl('manage', ['record' => $record->getKey()]))
            ->label('Manage Workers');
    }

Gaming

Programming

How do I create a custom Table Action